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25 Dec 2025, 06:32
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Bunuel
1) As the vistor count is different, and the range is atmost 12, the max visitor count can be either 38 or 39.
However, we can't get a concrete answer from just statement 1 .
Eliminate A and D.
2) The median visitor count is odd indicates that the middle two numbers are even. However, we can't get any additional information from that.
Eliminate B
Combination:
Combined we can conclude that the middle two numbers are 32 and 34, and the largest number is 39. Hence, the statements combined help get an answer to the question asked.
Option C
25 Dec 2025, 06:35
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12 consecutive days, smallest count 27
Test statement 1
range<12
largest <27+12=39
largest is any in the range<39
INSUFFICIENT
Test statement 2
12 distinct ordered x1<x2<...<x12
median (x6+x7)/2=33 x6+x7=66
many satisfy the smallest 27, largest is not determined
INSUFFICIENT
both
to get median 33 with 12 distinct integers in (27,39) exclude 33 so x6=32 and x7=34 average=33
makes largest 39
Both statements together are sufficient, but each alone is not.
Test statement 1
range<12
largest <27+12=39
largest is any in the range<39
INSUFFICIENT
Test statement 2
12 distinct ordered x1<x2<...<x12
median (x6+x7)/2=33 x6+x7=66
many satisfy the smallest 27, largest is not determined
INSUFFICIENT
both
to get median 33 with 12 distinct integers in (27,39) exclude 33 so x6=32 and x7=34 average=33
makes largest 39
Both statements together are sufficient, but each alone is not.
25 Dec 2025, 07:13
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A museum had different number of visitor for consecutive 12 days and the small count was 27.
We need to know the largest daily visitor count
Lets check given statements 1 by 1
Statement(1) - The range of the visitor counts for the 12 days at most 12
Min = 27
Range = Max - Min
=> 12 = Max - 27
=> Max = 39
Since at most is given, Max <= 39
With 12 distinct integers, minimum possible range is 11
Therefore the max value can be 38 or 39
=> Statement (1) is not sufficient
Statement (2) - The median visitor count over the 12 days was 33
Median = Average of 6th and 7th numbers in an ordered set
=> Median = 66/2 = 33
Now possible values for this would be (32,34) , (31,35) , (30,36) etc.
But, we know that min value is 27 and every day distinct number of visitors come
=> Possible value = {27,28,29,30,31,32,34,35,...}
Rest of the values wont fit to be in 6th or 7th places
But again max values can be anything
=> Statement(2) is not sufficient
Combining (1) and (2),
Range is atmost 12
=> Max value can be 38 or 39
The first 7 values have to be {27,28,29,30,31,32,34,..}
The remaining 5 values have to be >34 and <= 39 , and this is only possible when max value is 39
C. Both statement together are sufficient but neither alone is sufficient
We need to know the largest daily visitor count
Lets check given statements 1 by 1
Statement(1) - The range of the visitor counts for the 12 days at most 12
Min = 27
Range = Max - Min
=> 12 = Max - 27
=> Max = 39
Since at most is given, Max <= 39
With 12 distinct integers, minimum possible range is 11
Therefore the max value can be 38 or 39
=> Statement (1) is not sufficient
Statement (2) - The median visitor count over the 12 days was 33
Median = Average of 6th and 7th numbers in an ordered set
=> Median = 66/2 = 33
Now possible values for this would be (32,34) , (31,35) , (30,36) etc.
But, we know that min value is 27 and every day distinct number of visitors come
=> Possible value = {27,28,29,30,31,32,34,35,...}
Rest of the values wont fit to be in 6th or 7th places
But again max values can be anything
=> Statement(2) is not sufficient
Combining (1) and (2),
Range is atmost 12
=> Max value can be 38 or 39
The first 7 values have to be {27,28,29,30,31,32,34,..}
The remaining 5 values have to be >34 and <= 39 , and this is only possible when max value is 39
C. Both statement together are sufficient but neither alone is sufficient
!
How does this make a difference when we're looking at 12 consecutive days but? It does.
