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28 Apr 2026, 19:00
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A freight train traveled from North Terminal to East Terminal at a constant speed, without making any stops. At what time did the train arrive at East Terminal?
(1) The train departed North Terminal at 1:50 p.m.
(2) At 3:20 p.m., the train had completed 1/2 of the trip, and at 3:50 p.m., it had completed 2/3 of the trip.
The OA will be automatically revealed on Saturday 2nd of May 2026 07:00:13 PM Pacific Time Zone
(1) The train departed North Terminal at 1:50 p.m.
(2) At 3:20 p.m., the train had completed 1/2 of the trip, and at 3:50 p.m., it had completed 2/3 of the trip.
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The OA will be automatically revealed on Saturday 2nd of May 2026 07:00:13 PM Pacific Time Zone
28 Apr 2026, 21:38
Kudos
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Constant speed → distance ∝ time
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Statement (2):
At 3:20 → 1/2 of trip
At 3:50 → 2/3 of trip
So in 30 minutes:
distance covered = (2/3 − 1/2) = 1/6
⇒ 1/6 distance = 30 minutes
Total trip = 6 × 30 = 180 minutes = 3 hours
So from 3:20 (halfway), remaining half takes 1.5 hours
Arrival time = 3:20 + 1:30 = 4:50 p.m.
⇒ Statement (2) alone is sufficient
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Statement (1):
Given only departure time = 1:50 p.m.
No info about speed or distance
⇒ Not sufficient
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Final Answer: B
---
Hope this helps.
If you need anything, feel free to tag me — happy to go through it.
– Rajdeep
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Statement (2):
At 3:20 → 1/2 of trip
At 3:50 → 2/3 of trip
So in 30 minutes:
distance covered = (2/3 − 1/2) = 1/6
⇒ 1/6 distance = 30 minutes
Total trip = 6 × 30 = 180 minutes = 3 hours
So from 3:20 (halfway), remaining half takes 1.5 hours
Arrival time = 3:20 + 1:30 = 4:50 p.m.
⇒ Statement (2) alone is sufficient
---
Statement (1):
Given only departure time = 1:50 p.m.
No info about speed or distance
⇒ Not sufficient
---
Final Answer: B
---
Hope this helps.
If you need anything, feel free to tag me — happy to go through it.
– Rajdeep
28 Apr 2026, 22:49
Kudos
Bookmarks
Statement 1:
We know nothing about the speed and distance.
INSUFFICIENT.
Statement 2:
From this we can find the speed:
2/3x-1/2x = 1/6x = Distance travelled in 30 mins = 1/2 hr.
Speed = 1/6x / 1/2 = 1/3x.
At 3:50 2/3rd complete, so remaining = 1/3rd.
1/3x / 1/3 = 1hr more.
3:50 + 1hr = 4:50 he will arrive at East Terminal.
SUFFICIENT.
Answer: Option B
We know nothing about the speed and distance.
INSUFFICIENT.
Statement 2:
From this we can find the speed:
2/3x-1/2x = 1/6x = Distance travelled in 30 mins = 1/2 hr.
Speed = 1/6x / 1/2 = 1/3x.
At 3:50 2/3rd complete, so remaining = 1/3rd.
1/3x / 1/3 = 1hr more.
3:50 + 1hr = 4:50 he will arrive at East Terminal.
SUFFICIENT.
Answer: Option B
Bunuel
