Last visit was: 05 Sep 2026, 19:04 It is currently 05 Sep 2026, 19:04
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 05 Sep 2026
Posts: 113,155
Own Kudos:
839,386
 [1]
Given Kudos: 111,332
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 113,155
Kudos: 839,386
 [1]
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
Most Helpful Reply
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 05 Sep 2026
Posts: 113,155
Own Kudos:
Given Kudos: 111,332
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 113,155
Kudos: 839,386
Kudos
Add Kudos
Bookmarks
Bookmark this Post
General Discussion
User avatar
GMATcracker101
Joined: 24 May 2025
Last visit: 05 Sep 2026
Posts: 49
Own Kudos:
Given Kudos: 25
Products:
Posts: 49
Kudos: 32
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
Usernamevisible
Joined: 09 Jun 2022
Last visit: 05 Sep 2026
Posts: 480
Own Kudos:
Given Kudos: 1,282
Products:
Posts: 480
Kudos: 111
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Given:

J + K = 1/6

Need: J + K + L

---

(1)

K = 1/15

J = 1/6 − 1/15 = 1/10

L unknown.

Not sufficient.

---

(2)

J + L take half as long as J + K.

J + K = 6 hours ⇒ J + L = 3 hours

So:

J + L = 1/3

Knowing J + K = 1/6 and J + L = 1/3 does not determine L.

Not sufficient.

---

(1) + (2)

J = 1/10

L = 1/3 − 1/10 = 7/30

J + K + L
= 1/10 + 1/15 + 7/30
= 2/5

Time = 1 ÷ (2/5) = 5/2 = 2.5 hours

Sufficient.

Answer: C.
User avatar
rockstar09rulez
Joined: 30 Sep 2023
Last visit: 26 Aug 2026
Posts: 43
Own Kudos:
Given Kudos: 74
Location: United States (CA)
Concentration: Technology, Finance
Products:
Posts: 43
Kudos: 25
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Let j, k, l take j, k, and h hours respectively. Work = w

Working together: W = R * T
w = (w/6 + 2/l) * time
So, to get time we need the value of l

Stmt 1: k takes 15 hours, but this tells us nothing about l. This statement can help us get to j, but we won't be able to find l. INSUFF
Stmt 2: will give us an equation in j and l. Again insuff, since we don't have the value of j to find l. We only have combined rate of j and k available.

1 and 2 together - From statement 1, we get j and put in the result of Stmt 2 to get l. SUFF. Hence (C) is the answer
User avatar
nammolestias
Joined: 13 Jan 2026
Last visit: 05 Sep 2026
Posts: 65
Own Kudos:
Given Kudos: 23
Location: India
Concentration: Finance, Strategy
GPA: 8.38
WE:Analyst (Finance: Investment Management)
Products:
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
Machines \(J\), \(K\), and \(L\) each operate at a constant rate. \(J\) and \(K\), working together, can complete a given order in 6 hours. How long will it take \(J\), \(K\), and \(L\), working together, to complete the order?

(1) Machine \(K\) operating alone takes 15 hours to complete the order.
(2) Machines \(J\) and \(L\), working together, take half as long as \(J\) and \(K\) do.
pre thinking =j+k=1/6

statement 1)k=1/15
solving j+(1/15)=1/6
j=1/10
we also want to find time taken by l to find time taken by j+k+l
therefore insufficient

statement 2)from here we get to know j+l=(j+k)/2 which is insufficient

combining both statement we get the ans hence sufficient
User avatar
vasu1104
Joined: 10 Feb 2023
Last visit: 04 Sep 2026
Posts: 732
Own Kudos:
Given Kudos: 672
Location: Canada
Products:
Posts: 732
Kudos: 422
Kudos
Add Kudos
Bookmarks
Bookmark this Post
rate for j = x
rate for k = y
rate for l = p

when j and k work together, time taken is 6 hr.
so a = (x+y)6

find = time taken when all three work together.
say work = a

time for all three= work/ rate = a / x+y+p
we can put value of a in here.

6(x+y) / x+y+p. basically we need to find this equation.

S-1
K takes 15 hrs.
a = 15y
but we cant use this into eqn.
not sufficient.

S-2
time for J and L together = a/ x+p
time for j and K together = a/x+y

a/x+p = (1/2) (a/x+y)

but not enough to get us to ans.
not sufficient.

S-1&2

we know a= 15y.
and we also know time taken when j and k work together.
its a = 6(x+y)
use a value in here and find one variable in terms of other.

15y = 6x+6y
6x= 9y
x= 3y/2

now from S-2 we can find value of p.

a/x+p = (1/2) (a/x+y)

x+p = 2(x+y)
p= x +2y

now in our actual eqn, we can put value of p and also value of x in terms of y.

upon doing it, we can easily find the ans.

Choice C

Bunuel
Machines \(J\), \(K\), and \(L\) each operate at a constant rate. \(J\) and \(K\), working together, can complete a given order in 6 hours. How long will it take \(J\), \(K\), and \(L\), working together, to complete the order?

(1) Machine \(K\) operating alone takes 15 hours to complete the order.
(2) Machines \(J\) and \(L\), working together, take half as long as \(J\) and \(K\) do.
Moderators:
Math Expert
113155 posts
DI Forum Moderator
409 posts