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07 Feb 2021, 14:29
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C
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Difficulty:
65%
(hard)
Question Stats:
61% (02:01) correct
39%
(02:13)
wrong
based on 279
sessions
History
Date
Time
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Not Attempted Yet
A train crosses a man standing on a platform 150 meters long in 10 seconds and crosses the platform completely in 22 seconds. What is the length of the train?
A. 90 meters
B. 100 meters
C. 125 meters
D. 150 meters
E. 180 meters
A. 90 meters
B. 100 meters
C. 125 meters
D. 150 meters
E. 180 meters
Approach: Time and Distance
\(\texttt{Speed} = \dfrac{\texttt{Distance}}{\texttt{Time}} = k (\text{constant})\)
Let's consider the length of the train be \(x\) m.
Therefore, \(\dfrac{x}{10} = \dfrac{150+x}{22}\).
To cross the platform completely, the length of the train and the platform is combined, which crosses in \(22\) sec.
\(x=\dfrac{150 \times 10}{12}=5 \times 25 = 125\) m
ANS C
\(\texttt{Speed} = \dfrac{\texttt{Distance}}{\texttt{Time}} = k (\text{constant})\)
Let's consider the length of the train be \(x\) m.
Therefore, \(\dfrac{x}{10} = \dfrac{150+x}{22}\).
To cross the platform completely, the length of the train and the platform is combined, which crosses in \(22\) sec.
\(x=\dfrac{150 \times 10}{12}=5 \times 25 = 125\) m
ANS C
General Discussion
07 Feb 2021, 21:23
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speed of train = 150/10-> 15 mts/sec
(length of train+length of platform)= 15* 22 sec=330
hence length of train=330-150=180
(length of train+length of platform)= 15* 22 sec=330
hence length of train=330-150=180
