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05 Feb 2022, 04:26
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C
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Difficulty:
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74% (01:49) correct
26%
(02:28)
wrong
based on 502
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A predator is chasing its prey. The predator takes 4 leaps for every 6 leaps of the prey and the predator covers as much distance in 2 leaps as 3 leaps of the prey. What is the ratio of the speed of the predator to that of the prey ?
(A) 11 : 9
(B) 10 : 9
(C) 1 : 1
(D) 9 : 10
(E) 9 : 11
(A) 11 : 9
(B) 10 : 9
(C) 1 : 1
(D) 9 : 10
(E) 9 : 11
Attachment:
Prey.png
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04 Mar 2024, 09:41
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Official Solution:
A predator is chasing its prey. The predator takes 4 leaps for every 6 leaps of the prey, and the predator covers as much distance in 2 leaps as 3 leaps of the prey. What is the ratio of the speed of the predator to that of the prey?
A. 11 : 9
B. 10 : 9
C. 1 : 1
D. 9 : 10
E. 9 : 11
Assuming one leap of the predator is \(x\) units and one leap of the prey is \(y\) units, then:
In 4 leaps, the predator covers the distance of \(4x\) units.
In 6 leaps, the prey covers the distance of \(6y\) units.
Note that these distances take the predator and the prey the same amount of time.
Since it is also given that the predator covers as much distance in 2 leaps as the prey does in 3 leaps, we get \(2x = 3y\). Substituting \(2x = 3y\) in the above, we get \(6y = 2(3y) = 4x\).
Thus, in the same time period, both the predator and the prey cover the same distance of \(4x\) units, indicating an equal speed.
Answer: C
A predator is chasing its prey. The predator takes 4 leaps for every 6 leaps of the prey, and the predator covers as much distance in 2 leaps as 3 leaps of the prey. What is the ratio of the speed of the predator to that of the prey?
A. 11 : 9
B. 10 : 9
C. 1 : 1
D. 9 : 10
E. 9 : 11
Assuming one leap of the predator is \(x\) units and one leap of the prey is \(y\) units, then:
In 4 leaps, the predator covers the distance of \(4x\) units.
In 6 leaps, the prey covers the distance of \(6y\) units.
Note that these distances take the predator and the prey the same amount of time.
Since it is also given that the predator covers as much distance in 2 leaps as the prey does in 3 leaps, we get \(2x = 3y\). Substituting \(2x = 3y\) in the above, we get \(6y = 2(3y) = 4x\).
Thus, in the same time period, both the predator and the prey cover the same distance of \(4x\) units, indicating an equal speed.
Answer: C
General Discussion
kungfury42
Joined: 07 Jan 2022
Last visit: 31 May 2023
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Given Kudos: 724
Schools: NUS '25 (A)
GMAT 1: 740 Q51 V38
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05 Feb 2022, 13:48
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Let the prey cover a distance of D in each leap. Total distance it covers in 3 leaps = 3D which is equal to the total distance the predator covers in 2 leaps which means the total distance predator covers in each leap = 3D/2 = 1.5D
Now distance covered by prey in 6 leaps = 6D
Distance covered by predator in 4 leaps = 4*1.5D = 6D
And we've been given that both of them take the same time to do so (making 6 leaps and 4 leaps respectively)
If time is constant, Distance is directly proportional to speed and since distance is the same too (in this case), their speeds will also be equal.
Therefore, ratio of their speeds = 1:1, hence, option C.
Posted from my mobile device
Now distance covered by prey in 6 leaps = 6D
Distance covered by predator in 4 leaps = 4*1.5D = 6D
And we've been given that both of them take the same time to do so (making 6 leaps and 4 leaps respectively)
If time is constant, Distance is directly proportional to speed and since distance is the same too (in this case), their speeds will also be equal.
Therefore, ratio of their speeds = 1:1, hence, option C.
Posted from my mobile device
