Is y greater than y^2? (1) y is greater than -1 (2) y^2 is greater the

Question

Competition Mode Question

Is y greater than y^2?

(1) y is greater than -1.
(2) y^2 is greater than 1.

sampriya · Answer

Is y greater than y^2?

(1) y is greater than -1.

y= 2 yes
y=0.5 no

(2) y^2 is greater than 1.

y<-1 y>1

option B is sufficient

since only the values between -1<y<1; y is greater than y^2

madgmat2019 · Answer

(1) y is greater than -1.
(2) y^2 is greater than 1.

Clearly both individually cannot help in knowing whether y > y^2

Now by combining both 
1) y>-1.....-0.5,0,0.5,1,2....
2) y^2>1..... -1>y>1....-3,-2.5,-2,-1.5,1.5,2...

Both y>y^2 and y<y^2 are possible

OA:E

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vg18 · Answer

Is y greater than y^2? q: y>y^2? y-y^2>0 Solving for y : is 01. Therefore, range is y>1, y<-1. Again Insufficient. Combining, y>1. Ans C

Archit3110 · Answer

to check
y>y^2
#1
 y is greater than -1.
y>-1
y can be -1/2 , 0 we get no
or y = +1/2 , 2we get yes
insufficeint
#2
y^2>1
y can be + or -ve integer
sufficient 
as in that case y>y^2 ; not possible
IMO B

(1) y is greater than -1.
(2) y^2 is greater than 1.

unraveled · Answer

Is y greater than y^2 ? y > y^2 y - y^2 > 0 y(1 - y) > 0 0 < y < 1 ? (1) y is greater than -1. y = \frac{-1}{2} NO y = \frac{1}{2} INSUFFICIENT. (2) y^2 is greater than 1. y^2 > 1 y^2 - 1 > 0 (y - 1)(y + 1) > 0 y > 1, y > -1 SO y > 1 y = 2 NO y = 3 NO SUFFICIENT. Answer B.

exc4libur · Answer

y>y^2 when 01 then y>1 or y<-1; so y is not a proper fraction. Answer (B)

exc4libur · Answer

y>y^2 when 01 then y>1 or y<-1; therefore y is not a proper fraction. Answer (B)

suchithra · Answer

Is y>y^{2} (1) y is greater than -1. y>-1 i.e y can be \frac{-1}{2},0,\frac{1}{2} ,1 etc When Y= -\frac{1}{2} , is y>y^{2} ? i,e is \frac{-1}{2}>\frac{1}{4} ? NO When Y is 0, is y>y^{2} ? ie is 0<0 ? NO When y is \frac{1}{2} , is \frac{1}{2}>\frac{1}{4} , YES Therefore Not Sufficient (2) y^{2}>1 y can be -infinity \frac{9}{4}? , NO If Y is 2, Is 2>4, NO If Y is \frac{3}{2} , Is \frac{3}{2}>\frac{9}{4} ?NO Therfore B is sufficient. Answer is B

Raxit85 · Answer

Is y greater than y^2?

Is y> y^2?

(1) y is greater than -1. If y = -1/2, then y> y^2 will not be true and if y = 1/2, then y> y^2 will be true. Hence insufficient.

(2) y^2 is greater than 1. - It means y can be -ve or +ve. e.g. y = -2, then y> y^2 will not be true and y = 2, then y> y^2 will not be true. If we take lowest value of y^2 = 1.02 having y as + or - 1.01, then the answer will be confirm no. 
Hence sufficient.

Imo. B

eakabuah · Answer

We are to determine if y>y^2.

1. y>-1
Not sufficient. This is because if y=1/2, then y^2=14 and y(1/2)>y^2 (1/4). But if y=2, then y^2=4 and y<y^2.

2. y^2>1
Sufficient.
y^2>1
y^2-1>0
(y-1)(y+1)>0
This is only true when y<-1 or y>1
with y<-1, y^2 (a positive number) is always greater than y (a negative number).
with y>1, y^2 is always greater than y.
Statement 2 is therefore sufficient.

The answer is therefore B.

CareerGeek · Answer

(1) y is greater than -1.
If 0 < y < 1, y is greater than y^2
If y > 1, y is less than y^2
—> Two different outcomes —> Insufficient

(2) y^2 is greater than 1.
—> y is either less than -1 or y is greater than 1
Case 1: y < -1, y is always less than y^2, since y^2 is always positive

Case 2: y > 1, y is always less than y^2,

—> y is never greater than y^2. A definite NO
—> Sufficient

IMO Option B

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lacktutor · Answer

Is y greater than y^2? —> y > y^{2} y*(y —1)< 0 —> 0 < y < 1? (Statement1): y > —1 If y= 0.5, then YES If y= —0.5, then NO Insufficient (Statement2): y^{2}> 1 (y—1)*(y+1) >0 —> y <—1 and y >1 (Always NO) Sufficient The answer is B Posted from my mobile device

Is y greater than y^2? (1) y is greater than -1 (2) y^2 is greater the

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