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02 Nov 2015, 08:33
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B
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66% (01:40) correct
34%
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wrong
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All of the tickets for 2 music concerts, X and Y, were either purchased or given away, and the ratio of X tickets to Y was 2 to 1. Of the total number of X tickets and Y tickets, what percentage was purchased?
(1) The total number of X tickets and Y tickets, is 240.
(2) Of the X tickets, exactly 60% were purchased, and of the Y tickets, exactly 80% were purchased.
(1) The total number of X tickets and Y tickets, is 240.
(2) Of the X tickets, exactly 60% were purchased, and of the Y tickets, exactly 80% were purchased.
02 Nov 2015, 11:39
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All of the tickets for 2 music concerts, X and Y, were either purchased or given away, and the ratio of X tickets to Y was 2 to 1. Of the total number of X tickets and Y tickets, what percentage was purchased?
(1) The total number of X tickets and Y tickets, is 240.
(2) Of the X tickets, exactly 60% were purchased, and of the Y tickets, exactly 80% were purchased.
x/y = 2/1 => x=2y
St 1:
The total number of X tickets and Y tickets, is 240.
x + y = 240; 2y + y = 240
=> y=80 and x=160. But no relevant info about how many tickets were purchased from both.
This is not sufficient.
St2 :
Of the X tickets, exactly 60% were purchased, and of the Y tickets, exactly 80% were purchased.
No of tickets purchased by X = 60% of 2y = 1.2y
No of tickets purchased by Y = 80% of y = 0.8y
Total tickets sold is 2y out of 3y, which gives 66.66%
Another method :
Plugging in numbers, Let x=200 and y=100
60% of 200 is 120, 80% of 100 is 80
Total sales 120+80 = 200 out of 300, which gives the same 66.66%. (same happens with 1st stmt data).
This is sufficient.
Ans B.
(1) The total number of X tickets and Y tickets, is 240.
(2) Of the X tickets, exactly 60% were purchased, and of the Y tickets, exactly 80% were purchased.
x/y = 2/1 => x=2y
St 1:
The total number of X tickets and Y tickets, is 240.
x + y = 240; 2y + y = 240
=> y=80 and x=160. But no relevant info about how many tickets were purchased from both.
This is not sufficient.
St2 :
Of the X tickets, exactly 60% were purchased, and of the Y tickets, exactly 80% were purchased.
No of tickets purchased by X = 60% of 2y = 1.2y
No of tickets purchased by Y = 80% of y = 0.8y
Total tickets sold is 2y out of 3y, which gives 66.66%
Another method :
Plugging in numbers, Let x=200 and y=100
60% of 200 is 120, 80% of 100 is 80
Total sales 120+80 = 200 out of 300, which gives the same 66.66%. (same happens with 1st stmt data).
This is sufficient.
Ans B.
saikiransomala
Joined: 10 Apr 2015
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Given Kudos: 101
Location: India
Concentration: Healthcare, Strategy
Schools: HKU'16 (D) ISB '17 (D) CEIBS '18 (A) CUHK '17 (A)
GMAT 1: 680 Q49 V34
GPA: 2.4
WE:Marketing (Healthcare/Pharmaceuticals)
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02 Nov 2015, 22:28
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Hi,
Using statement 1 along with Premise, we arrive at Tx = 160 and Ty =80 but we can not arrive at the ratio of Px and Py. So Statement 1 is insufficient
Using statement 2 along with Premise,
Px:Py = 3/5Tx / (4/5Ty) = 3/5 * 5/4 * 2/1 = 3/2 (We know from the premise that Tx/Ty = 2:1)
Hence Option B.
Tx = Total tickets of X concert (Purchase plus given)
Ty= Total tickets of Y
Px and Py = Purchase tickets of X and Y
Gx and Gy = Given tickets of X and Y
Using statement 1 along with Premise, we arrive at Tx = 160 and Ty =80 but we can not arrive at the ratio of Px and Py. So Statement 1 is insufficient
Using statement 2 along with Premise,
Px:Py = 3/5Tx / (4/5Ty) = 3/5 * 5/4 * 2/1 = 3/2 (We know from the premise that Tx/Ty = 2:1)
Hence Option B.
Tx = Total tickets of X concert (Purchase plus given)
Ty= Total tickets of Y
Px and Py = Purchase tickets of X and Y
Gx and Gy = Given tickets of X and Y
04 Nov 2015, 20:03
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Bunuel
Ans: B
Solution: question stem tells us that x:y = 2:1 means x=2n and y=n total 3n tickets.
1) this gives is number of tickets total and in x and y but no info is given to get to the purchased or give away [Not Sufficient]
2) this says 60*2n/100 and 80*n/100 are purchased = 2n are purchased
here we know total tickets = 3n and purchsed are 2n we can get the required percentage from this [Sufficient]
Ans:B
