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Question Stats:
60%
(02:12)
correct 40%
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wrong
based on 47
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A man purchased some pens, pencils and erasers. Can the number of erasers purchased be 3?
(1) The ratio of the number of pens to the number of pencils was the same as the ratio of the number of pencils to the number of erasers. (2) Total number of items purchased was 21.
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Originally posted by Luckisnoexcuse on 05 Jul 2017, 00:46.
Last edited by Luckisnoexcuse on 27 Sep 2017, 21:21, edited 1 time in total.
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Bunuel
A man purchased some pens, pencils and erasers. Can the number of erasers purchased be 3?
(1) The ratio of the number of pens to the number of pencils was the same as the ratio of the number of pencils to the number of erasers. (2) Total number of items purchased was 21.
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(1) gives us
Pen : Pencil : Eraser if the ratio is
3:3:3 then we can say Yes
but if the ratio is 1:3:9 then its No Not sufficient
(2) Total is 21
Now Pen : Pencil : Eraser x:y:z x+y+z = 21 Not sufficient
On combining x/y=y/z y^2 = xz
Lets take one example y = 6 and x = 12 and y = 3 Pen : Pencil : Eraser 12:6:3 answer would be Yes
"Can the number of erasers purchased be 3" Yes possible
A man purchased some pens, pencils and erasers. Can the number of erasers purchased be 3?
(1) The ratio of the number of pens to the number of pencils was the same as the ratio of the number of pencils to the number of erasers. (2) Total number of items purchased was 21.
Show more
Answer C
Solution:
Let the number of pen be X, the number of pencil be Y, the number of Erasers be Z.
A man purchased some pens, pencils and erasers. Can the number of erasers purchased be 3?
(1) The ratio of the number of pens to the number of pencils was the same as the ratio of the number of pencils to the number of erasers. (2) Total number of items purchased was 21.
Answer C
Solution:
Let the number of pen be X, the number of pencil be Y, the number of Erasers be Z.
Statement 2 - X + Y + Z = 21 -------------------------------------------------Equation II
Y can be any number.
Statement 2 Not sufficient
Together 1 & 2:
From equation 1 \(Y^2\) = Can only be equal to 4,9,16, and 25. so, Y can be 2, 3, 4, 5.
Only when X = 16, Z = 1 and Y = 4 will satisfy both of the above equations.
hence Y = 4 and not 3 so
Together both the statements are sufficient. C
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consider, there are 6 pencils, 12 pens and 3 erasures. then also pencil^2= pens*erasures holds. 6^2=36 12*3=36. Answer would still remain C. Because we are asked to find "can the numbers of erasures purchased be 3?" So, yes in one scenario it can be.
A man purchased some pens, pencils and erasers. Can the number of erasers purchased be 3?
(1) The ratio of the number of pens to the number of pencils was the same as the ratio of the number of pencils to the number of erasers. (2) Total number of items purchased was 21.
Show more
Hi Bunuel, may be you require to look into the Q ...
the wordings are CAN the erasers be 3...
(1) The ratio of the number of pens to the number of pencils was the same as the ratio of the number of pencils to the number of erasers. let the ratio be 1:1:1...all three can be 3 each 3:3:3... YES erasers CAN be 3 also each can be 4:4:4 that is 4 each... ans is No
BUt we are looking for CAN, so ans is YES and should be sufficient
(2) Total number of items purchased was 21 x+y+z=21... we can easily find the match where erasers are 3 and remaining two add up to 18 so again should be suffficient..
But if the Q was "IS number of erasers purchased 3", each statement would be insuff two solution that will fit in.. 1) 12:6:3.....12+6+3=21....Also ratio is 12:6 or 2:1 and 6:3 or 2;1.... 6^2=12*3... so eraser can be 3 2) 16:4:1...16+4+1=21...Also ratio is 16:4=4:1 and 4:1....4^2=16*1...... so eraser will not be 3
and answer should be E for "is number of erasers 3?".. and ans should be D for " can the number of erasers be 3?"
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.