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11 Dec 2018, 01:46
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
56% (01:20) correct
44%
(01:39)
wrong
based on 150
sessions
History
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What is the value of (2a + b)/(a + b)?
(1) 3a/(a + b) = 7
(2) a + b = 3
(1) 3a/(a + b) = 7
(2) a + b = 3
11 Dec 2018, 01:57
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From statement 1:
\(\frac{3a}{(a+b)} = 7\)
\(a+b = \frac{3a}{7}\)
\(\frac{(2a+b)}{(a+b)}\) = \(\frac{(a+a+b)}{(a+b)}\) = \((a+\frac{3a}{7})/(\frac{3a}{7})\) = \((\frac{10a}{7})*(\frac{7}{3a})\) = \(\frac{10}{3}\)
Sufficient.
From statement 2:
\(a+b = 3\).
\(\frac{(2a+b)}{(a+b)}\) = \(\frac{(a+3)}{3}\)
Insufficient
A is the answer.
\(\frac{3a}{(a+b)} = 7\)
\(a+b = \frac{3a}{7}\)
\(\frac{(2a+b)}{(a+b)}\) = \(\frac{(a+a+b)}{(a+b)}\) = \((a+\frac{3a}{7})/(\frac{3a}{7})\) = \((\frac{10a}{7})*(\frac{7}{3a})\) = \(\frac{10}{3}\)
Sufficient.
From statement 2:
\(a+b = 3\).
\(\frac{(2a+b)}{(a+b)}\) = \(\frac{(a+3)}{3}\)
Insufficient
A is the answer.
31 Aug 2021, 20:01
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What is the value of [2a + b]/ [a + b]?
1) [3a]/ [a + b] = 7
2) a+ b = 3
Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
EACH statement ALONE is sufficient.
Statements (1) and (2) TOGETHER are NOT sufficient.
Hello, anyone know why the answer is A and not C?
1) [3a]/ [a + b] = 7
2) a+ b = 3
Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
EACH statement ALONE is sufficient.
Statements (1) and (2) TOGETHER are NOT sufficient.
Hello, anyone know why the answer is A and not C?
