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E
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Difficulty:
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Question Stats:
82% (01:31) correct
18%
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based on 1028
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Is the prime number p equal to 37?
(1) p = n^2 + 1, where n is an integer.
(2) p^2 is greater than 200.
(1) p = n^2 + 1, where n is an integer.
(2) p^2 is greater than 200.
09 Jul 2014, 02:57
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Is the prime number p equal to 37?
(1) p = n^2 + 1, where n is an integer. Prime p is 1 more than a perfect square. It could be 37, but it could also be other primes, for example, 5 or 17. Not sufficient.
(2) p^2 is greater than 200. 37^2 > 200, so p could be 37 but it could be any other prime greater than 13. Not sufficient.
(1)+(2) Still not sufficient. For example, p could be 37 or 17.
Answer: E.
P.S. Please read carefully and follow: rules-for-posting-please-read-this-before-posting-133935.html Pay attention to rules 2 and 3. Thank you.
(1) p = n^2 + 1, where n is an integer. Prime p is 1 more than a perfect square. It could be 37, but it could also be other primes, for example, 5 or 17. Not sufficient.
(2) p^2 is greater than 200. 37^2 > 200, so p could be 37 but it could be any other prime greater than 13. Not sufficient.
(1)+(2) Still not sufficient. For example, p could be 37 or 17.
Answer: E.
P.S. Please read carefully and follow: rules-for-posting-please-read-this-before-posting-133935.html Pay attention to rules 2 and 3. Thank you.
General Discussion
Temurkhon
Joined: 23 Jan 2013
Last visit: 06 Apr 2019
Posts: 408
Own Kudos:
Given Kudos: 43
Schools: Cambridge'16
07 Jul 2015, 06:13
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St1. p=n^2+1, so if n+6, p=37 but if n=10, p=101. INSUFF
St2. p^2>200 => p>sqrt200 => p>14, again p can be 37 OR 101. INSUFF
St1+St2. INSUFF
E
St2. p^2>200 => p>sqrt200 => p>14, again p can be 37 OR 101. INSUFF
St1+St2. INSUFF
E
