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Updated on: 25 Aug 2013, 09:36
Originally posted by udaymathapati on 30 Aug 2010, 10:29.
Last edited by Bunuel on 25 Aug 2013, 09:36, edited 1 time in total.
Last edited by Bunuel on 25 Aug 2013, 09:36, edited 1 time in total.
Edited the answer choices.
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
57% (02:08) correct
43%
(02:14)
wrong
based on 58
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A certain list consists of 21 different numbers. If n is in the list and n is 4 times the average (arithmetic mean) of the other 20 numbers in the list, then n is what fraction of the sum of the 21 numbers in the list?
(A) 1/20
(B) 1/6
(C) 1/5
(D) 4/21
(E) 5/21
OPEN DISCUSSION OF THIS QUESTION IS HERE: a-certain-list-consists-of-21-different-numbers-if-n-is-in-103995.html
(A) 1/20
(B) 1/6
(C) 1/5
(D) 4/21
(E) 5/21
OPEN DISCUSSION OF THIS QUESTION IS HERE: a-certain-list-consists-of-21-different-numbers-if-n-is-in-103995.html
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30 Aug 2010, 11:15
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Looks like the answer is wrong.
series : a1, a2....a20,n
sum of a1+a2+...+a20 = 20*x (x = average)
so, n = 4*x
Hence, a1+a2+..+a20+n = 24x
So, the fraction asked = 4x/24x = 1/6
series : a1, a2....a20,n
sum of a1+a2+...+a20 = 20*x (x = average)
so, n = 4*x
Hence, a1+a2+..+a20+n = 24x
So, the fraction asked = 4x/24x = 1/6
30 Aug 2010, 22:15
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I also got the same answer - 1/6.
Given n = 4[(Sum of 21 elements - n)/20]
=> n = (Sum of 21 elements - n)/5
=> 5n = (Sum of 21 elements - n)
=> 6n = Sum of 21 elements.
Therefore n/(Sum of 21 elements) => n/6n
Answer should be 1/6.
@ udaymathapati -- Please confirm
Given n = 4[(Sum of 21 elements - n)/20]
=> n = (Sum of 21 elements - n)/5
=> 5n = (Sum of 21 elements - n)
=> 6n = Sum of 21 elements.
Therefore n/(Sum of 21 elements) => n/6n
Answer should be 1/6.
@ udaymathapati -- Please confirm
