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AnkitK
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Yeah Z is odd and 26 is even. It has to be zeroth power

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A = {3,-8,Y,19,-6}

B = {k,-3,0,16,-5,9}

Y > 21

So L = Median of A = 3

M = Mode of Set B

Z = (3)^M

If Z is a divisor of 26, (3)^M = 1 because 26 does not have 3 as a factor

=> M = 0

Hence k = 0, as M is mode and 0 will be the most frequently occuring number in set B.

Answer - C
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guys will u please tell me how long does it take u to solve questions like this....
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shalu
guys will u please tell me how long does it take u to solve questions like this....

There are few difficult ones in statistics, which may take well over 2 minutes. This particular one should not be more than 1min 20secs. The explanation may look convoluted and tedious. If you know about the basic concepts of mean, mode, median, range, std deviation and jot down only what's needed for the solution, omitting the aesthetics, you could even do it within a minute. Then again, I'd rather spend 20 seconds extra and solve a question correctly. Integrity holds the priority, however one must not be ignorant of the clock.
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this question is weird although i can guess the answer C.
because only C fits to find mode M
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AnkitK
Set A consists of integers {3, -8, Y, 19, -6} and set B consists of integers {k, -3, 0, 16, -5, 9}. Number L represents the median of set A, number M represents mode of set B and number Z = L^M. If Y is an integer greater than 21, for what value of k will Z be a divisor of 26?

A. -2
B. -1
C. 0
D. 1
E. 2

OPEN DISCUSSION OF THIS QUESTION IS HERE: set-a-126761.html

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