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Bunuel
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A young girl counted in the following way on the fingers of her left 05 Dec 2019, 01:50
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95% (hard)

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54% (02:56) correct 46% (02:39) wrong based on 198 sessions

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A young girl counted in the following way on the fingers of her left hand. She started calling the thumb 1, the index finger 2, middle finger 3, ring finger 4, little finger 5, then reversed direction, calling the ring finger 6, middle finger 7, index finger 8, thumb 9 and then back to the index finger for 10, middle finger for 11 and so on. She counted up 1994. She ended on her

A. thumb
B. the index finger
C. the middle finger
D. the ring finger
E. the little finger

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B
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A young girl counted in the following way on the fingers of her left Updated on: 05 Dec 2019, 02:50
Originally posted by zhanbo on 05 Dec 2019, 02:20.
Last edited by zhanbo on 05 Dec 2019, 02:50, edited 1 time in total.
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My answer is (B) - Index finger.

One complete round is 8. Starting from 9, 17, etc. the same pattern repeats.

So 1994 / 8 = 249 with 2 as remainder. 2 means index finger.

BTW: To be grammatically correct, delete "The" in the options b, c, d, and e.
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A young girl counted in the following way on the fingers of her left 05 Dec 2019, 02:46
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Bunuel
A young girl counted in the following way on the fingers of her left hand. She started calling the thumb 1, the index finger 2, middle finger 3, ring finger 4, little finger 5, then reversed direction, calling the ring finger 6, middle finger 7, index finger 8, thumb 9 and then back to the index finger for 10, middle finger for 11 and so on. She counted up 1994. She ended on her

A. thumb
B. the index finger
C. the middle finger
D. the ring finger
E. the little finger

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Explanation:

The thumb series is 1,9,17,25,33...
Therefore 8n+1=1994
8n=1993
remainder=1
Therefore thumb for 1993 and the next one is index.
The answer is the index finger.
IMO-B

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A young girl counted in the following way on the fingers of her left 05 Dec 2019, 03:20
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Please follow the attachment for better understanding:

Initial of fingers are written as T, I, M, R, L from left to write and
the counting as it would appear.
Now first row has 5 numbers from 1 to 5
so remaining = 1994-5= 1989
Now we see that each row has 4 numbers and
Let say row beginning from 6 be 1st row and call it odd
row beginning from 10 be 2nd row and call it even and so on
Now 1989/4 gives Quotient : 497 which is odd row and will end at Thumb Finger and remainder: 1 which is at Index Finger

Answer: B
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A young girl counted in the following way on the fingers of her left 05 Dec 2019, 04:11
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with the given sequence we know that even no will only be Index and ring finger
and for the given sequence the the thumb falls as 8n+1 ; at n=249 ; 1993 it will be thumb and 1994 it will be index finger
IMO B

Bunuel
A young girl counted in the following way on the fingers of her left hand. She started calling the thumb 1, the index finger 2, middle finger 3, ring finger 4, little finger 5, then reversed direction, calling the ring finger 6, middle finger 7, index finger 8, thumb 9 and then back to the index finger for 10, middle finger for 11 and so on. She counted up 1994. She ended on her

A. thumb
B. the index finger
C. the middle finger
D. the ring finger
E. the little finger

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A young girl counted in the following way on the fingers of her left 20 May 2026, 06:27
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