Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Apr 2301:30 AM EDT
-02:30 AM EDT
Struggling with GMAT Verbal as a non-native speaker? Harsh improved his score from 595 to 695 in just 45 days—and scored a 99 %ile in Verbal (V88)! Learn how smart strategy, clarity, and guided prep helped him gain 100 points.
Apr 2308:00 PM PDT
-09:00 PM PDT
Video explanations + diagnosis of 10 weakest areas + 150+ short videos + study plan!
Apr 2512:30 AM EDT
-01:30 AM EDT
At one point, she believed GMAT wasn’t for her. After scoring 595, self-doubt crept in and she questioned her potential. But instead of quitting, she made the right strategic changes. The result? A remarkable comeback to 695. Check out how Saakshi did it.
Apr 2610:00 AM EDT
-11:00 AM EDT
The Target Test Prep course represents a quantum leap forward in GMAT preparation, a radical reinterpretation of the way that students should study. Try before you buy with a 5-day, full-access trial of the course for FREE!
Apr 2711:00 AM EDT
-12:00 PM EDT
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors
Apr 2808:00 AM PDT
-11:00 AM PDT
Whether you are just beginning your MBA journey or fine-tuning your path to a 700+ score, GMAT Day is designed to give you a competitive edge.
13 Oct 2015, 11:27
Kudos
Bookmarks
N
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
(N/A)
Question Stats:
100% (00:52) correct
0%
(00:00)
wrong
based on 23
sessions
History
Date
Time
Result
Not Attempted Yet
Peter took a 52-card deck of cards and removed all small cards, all spades, and all clubs.
The only remaining cards were 10, Jack, Queen, King, and Ace in the suits of heart and
diamond. Of these 10 cards, he deals himself 5 cards. What is the probability that Peter
deals himself at least one pair of cards?
A. 7/10
B. 17/33
C. 55/63
D. 66/165
E. 18/25
Note- This is a question from GMATPill exam. I do not have the answer to this question.
The only remaining cards were 10, Jack, Queen, King, and Ace in the suits of heart and
diamond. Of these 10 cards, he deals himself 5 cards. What is the probability that Peter
deals himself at least one pair of cards?
A. 7/10
B. 17/33
C. 55/63
D. 66/165
E. 18/25
Note- This is a question from GMATPill exam. I do not have the answer to this question.
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Problem Solving (PS) Forum
Still interested in this question? Check out the "Best Topics" block below for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
13 Oct 2015, 12:09
Kudos
Bookmarks
gmatprep258
The only way that he doesn't deal a pair is if he deals 10,J,Q,K,A. So the probability of dealing a pair will be 1 - the probability of dealing 10,J,Q,K,A.
The total number of combinations is \(10*9*8*7*6\), which equals 30240
The number of ways to deal 10,J,Q,K,A or a variance of it is \(10*8*6*4*2\), which equals 3840
1 - 3840/30240 = 26400/30240. That will roughly equal 26/30, which when doubled is 52/60. That is very close to C, which is the answer. We can estimate on this problem because the answer choices are fairly far apart and because the other closest answer has a denominator of 25, which is not a factor of 30240.
C
13 Oct 2015, 14:49
Kudos
Bookmarks
gmatprep258
P(at least 1 pair) = 1 - P(no Pairs)
P(no pairs) = number of hands dealt with no pairs / total possible number of hands
Number of hands dealt with no pairs has to be 10 J Q K A but with differing suits of hearts and diamonds. Since there are only two suits to pick from for a hand of 5 cards (just like a Coin Flip problem) total number of hands with no pairs = 2^5 = 32
Total possible number of hands is 10 C 5 = 10*9*8*7*6/ 5*4*3*2*1 = 252
Therefore 1-32/252 = 1- 8/63 = 55/63
Answer C
