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I'd go with D.

Since the selection for both the multiples is random, the selection of all the three hundred multiples of three may be odd or even or a combination of both.

So, in the worst case (with all the odd multiples of three), 50% of the total selected is even.
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I am a bit confused in this question. Since, we are given multiples are chosen at random, it may happen that all the multiples of 3 chosen are EVEN or ODD or Mixture.

Hence, we will get different answers each time.

Bunuel, kindly help.
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abhimahna
I am a bit confused in this question. Since, we are given multiples are chosen at random, it may happen that all the multiples of 3 chosen are EVEN or ODD or Mixture.

Hence, we will get different answers each time.

kindly help.


When we say that the probability of getting a Heads in a single coin toss is 1/2, it implies that if the task is repeated for a great many number of times, chances are that we will get Heads half the times. Similarly, here we can observe that the possible chances of picking even multiples of 3 becomes 1/2 as every 2nd multiple is even. Example: 3, 6, 9, 12, 15, 18 etc

Hope it helps :)
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abhimahna
I am a bit confused in this question. Since, we are given multiples are chosen at random, it may happen that all the multiples of 3 chosen are EVEN or ODD or Mixture.

Hence, we will get different answers each time.

kindly help.


When we say that the probability of getting a Heads in a single coin toss is 1/2, it implies that if the task is repeated for a great many number of times, chances are that we will get Heads half the times. Similarly, here we can observe that the possible chances of picking even multiples of 3 becomes 1/2 as every 2nd multiple is even. Example: 3, 6, 9, 12, 15, 18 etc

Hope it helps :)

No, that I know. My concern here is you are assuming that the multiples of 3 are consecutive which is not given in the question.

We can have multiples of 3 like 3,9,15 and so on.
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Bunuel
Three hundred multiples of three are picked at random, and three hundred multiples of four are picked at random. Approximately what percentage of the six hundred selected numbers are even?

A. 100%
B. 75%
C. 66%
D. 50%
E. 33%


300 multiples of 4-all will be even
Now, with multiples of 3, we have 3,6,9,12-so every alternate multiple of 3 is even-so total multiples of 3 in 300 numbers=150
So total even multiples of 3 and 4=300+150=450
Answer=450/600=75% C
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Question seems incomplete
Answer can be 50% or 75 % or 100%
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abhimahna
I am a bit confused in this question. Since, we are given multiples are chosen at random, it may happen that all the multiples of 3 chosen are EVEN or ODD or Mixture.

Hence, we will get different answers each time.

Bunuel, kindly help.

Hi
Bunuel may be further able to clarify the wordings but my take..

The word APPROXIMATELY tells us that we may be talking of probability too...
So in 300 randomly picked multiples of 3, probability that they are even is 50%, so 150 and all 300 multiples of 4 will be even, thus 75%...

Had word APPROXIMATELY not been used, the Q would be clearly missing the answer and would be insufficient
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abhimahna


No, that I know. My concern here is you are assuming that the multiples of 3 are consecutive which is not given in the question.

We can have multiples of 3 like 3,9,15 and so on.

We are not assuming that only consecutive multiples are considered for this example.
Let me clarify. Choosing only odd multiples is one of the myriad possible scenarios. Let's say we have to choose only 2 multiples of 3. Someone picks 3 & 27. Someone else picks 6 and 9. Someone else 3 and 60. So on and so forth. What we observe here is when an infinite number of such samples are considered, 50% of them will have even multiples and 50% will have odd multiples because every 2nd multiple of 3 is even. As is the case with a coin toss, a person may get 100 Heads in a row, but when more samples are considered, the chances get closer to 1/2.
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abhimahna


No, that I know. My concern here is you are assuming that the multiples of 3 are consecutive which is not given in the question.

We can have multiples of 3 like 3,9,15 and so on.

We are not assuming that only consecutive multiples are considered for this example.
Let me clarify. Choosing only odd multiples is one of the myriad possible scenarios. Let's say we have to choose only 2 multiples of 3. Someone picks 3 & 27. Someone else picks 6 and 9. Someone else 3 and 60. So on and so forth. What we observe here is when an infinite number of such samples are considered, 50% of them will have even multiples and 50% will have odd multiples because every 2nd multiple of 3 is even. As is the case with a coin toss, a person may get 100 Heads in a row, but when more samples are considered, the chances get closer to 1/2.

I donot agree with you. Its just to convince oneself when the OA is presented. Had the OA absent, you would also have looking for the right answer. Sorry Mate, but I think we need to wait for Bunuel to get the clarity on this question.

chetan2u

Hi
Bunuel may be further able to clarify the wordings but my take..

The word APPROXIMATELY tells us that we may be talking of probability too...
So in 300 randomly picked multiples of 3, probability that they are even is 50%, so 150 and all 300 multiples of 4 will be even, thus 75%...

Had word APPROXIMATELY not been used, the Q would be clearly missing the answer and would be insufficient

Yes, I understand your point. But even if you take all multiples of 3 as ODD, you will get the answer as 50% which is also present in the options. Had the other possibility answers not present in options, we could have considered 75% and moved on. Lets wait for Bunuel now :-D
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Bunuel
Three hundred multiples of three are picked at random, and three hundred multiples of four are picked at random. Approximately what percentage of the six hundred selected numbers are even?

A. 100%
B. 75%
C. 66%
D. 50%
E. 33%


Can you please explain??

What if all the three hundred multiples of 3 which were picked at random were odd?

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