Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Apr 2212:30 AM EDT
-01:30 AM EDT
At one point, she believed GMAT wasn’t for her. After scoring 595, self-doubt crept in and she questioned her potential. But instead of quitting, she made the right strategic changes. The result? A remarkable comeback to 695. Check out how Saakshi did it.
Apr 1612:00 PM EDT
-11:59 PM EDT
You’re first to know: Save $200 on GMAT prep starting tomorrow, 4/13. Get 6 official practice tests and study with real questions. Be ready to save!
Apr 2301:30 AM EDT
-02:30 AM EDT
Struggling with GMAT Verbal as a non-native speaker? Harsh improved his score from 595 to 695 in just 45 days—and scored a 99 %ile in Verbal (V88)! Learn how smart strategy, clarity, and guided prep helped him gain 100 points.
Apr 2308:00 PM PDT
-09:00 PM PDT
Video explanations + diagnosis of 10 weakest areas + 150+ short videos + study plan!
Apr 2610:00 AM EDT
-11:00 AM EDT
The Target Test Prep course represents a quantum leap forward in GMAT preparation, a radical reinterpretation of the way that students should study. Try before you buy with a 5-day, full-access trial of the course for FREE!
Apr 2711:00 AM EDT
-12:00 PM EDT
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors
Apr 2808:00 AM PDT
-11:00 AM PDT
Whether you are just beginning your MBA journey or fine-tuning your path to a 700+ score, GMAT Day is designed to give you a competitive edge.
13 Jun 2017, 00:17
Kudos
Bookmarks
B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
(N/A)
Question Stats:
0% (00:00) correct
0%
(00:00)
wrong
based on 0
sessions
History
Date
Time
Result
Not Attempted Yet
2 trains each of length 120 metres move in the same direction. The faster train completely overtakes the slower one in 15 seconds. If the slower train were to move at half its speed, faster train would overtake it in 10 seconds. Find the speeds of the two trains (faster and slower respectively in m/s)
A. 48 and 16
B. 32 and 16
C. 48 and 32
D. 64 and 48
A. 48 and 16
B. 32 and 16
C. 48 and 32
D. 64 and 48
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Problem Solving (PS) Forum
Still interested in this question? Check out the "Best Topics" block below for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
sashiim20
Joined: 04 Dec 2015
Last visit: 05 Jun 2024
Posts: 608
Own Kudos:
Given Kudos: 276
Location: India
Concentration: Technology, Strategy
Schools: ISB '19 IIMB IIMA XLRI HEC Sept19 intake Rotman '21 NUS '21 NTU '20 Trinity MBA '20 Bocconi '21 Smurfit "21
WE:Information Technology (Consulting)
Schools: ISB '19 IIMB IIMA XLRI HEC Sept19 intake Rotman '21 NUS '21 NTU '20 Trinity MBA '20 Bocconi '21 Smurfit "21
Posts: 608
Kudos:
1,972
13 Jun 2017, 00:34
Kudos
Bookmarks
shashankism
Formula to find time to cross each other:
When 2 trains of lengths \(a\) \(meters\) and \(b\) \(meters\) are moving in same direction with speeds \(x\) \(m/s\) and \(y\) \(m/s\) respectively \((x > y)\), then the time taken to cross each other is \(= \frac{a + b}{x - y}\)
Given; 2 trains each of length \(120\) \(meters\).
Let the speed of faster train be \(x\) \(m/s\) and slower train be \(y\) \(m/s\).
Given, faster train completely overtakes the slower one in \(15\) \(seconds\). ie; time taken to cross each other = \(15 s\)
\(15 = \frac{120 + 120}{x - y}\) \(==>\) \(\frac{240}{x - y}\)
\(x - y = 16\)
\(y = x - 16\) -------------- (i)
If the slower train were to move at half its speed, faster train would overtake it in \(10\) \(seconds\).
Speed of slower train would become \(y/2\).
\(10 = \frac{240}{x - {y/2}}==>\) \(x - \frac{y}{2} = 24\) \(==>\) \(\frac{2x - y}{2}= 24\) \(==>\) \(2x - y = 48\) -------------------- (ii)
Substituting value of \(y\) from (i) in above equation (ii);
\(2x - (x - 16) = 48\) ==> \(2x - x + 16 = 48\)
\(x = 48 - 16 = 32\)
Therefore speed of faster train is \(32 m/s\)
Speed of slower train, \(y = x - 16\) \(==> 32 - 16 = 16\).
Speeds of trains are \(32\) \(m/s\) and \(16\) \(m/s\). Answer B...
_________________
Kindly press "+1 Kudos" to appreciate
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Problem Solving (PS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
Moderator:
