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Sir, is the generalization based on the assumption that another circle/disc is stationery?
If so, what will be the no. of revolutions when both discs are moving? Will it be n+1, n, n-1 or any other answer?
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Sir, is the generalization based on the assumption that another circle/disc is stationery?
If so, what will be the no. of revolutions when both discs are moving? Will it be n+1, n, n-1 or any other answer?


Hello rocky620. This is based on the other disc being stationery. If 2 discs move, then direction of movement and speed will come into play and that's relative speed and some physics too. Don't worry, as it is outside the scope of GMAT and you will not get questions like that.

Arun Kumar
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Thanks sir, so by default the second disc will always be stationery?
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Look at the picture. There are three figures.

Figure 1: If it would've been a straight line rather than a circle.

Figure 2: If it would've applied Figure 1's logic to a circle.

Figure 3: How it would actually look.



Hope this helps.
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I think the best way to visualize this is to think of the Circle A going around a Square instead of a Circle (both are 360 Degrees Total)


At each Corner/Vertex of the Square, Circle A will have to make a Rotation of 90 Degrees WITHOUT having made any headway around the Larger Square. Circle A will have to make this 90 Degree Rotation in order to change directions, NOT move forward around the Square.

Making this "in place" Rotation 4 Times at each Vertex = ONE 360 Degree Rotation Circle A makes without having added any Distance around the Square.


This same exact occurrence is happening around Circle B, just that it is spread out "smoothly" over the entire 360 Degrees of Circle B. There are no abrupt 90 Degree Rotations like there were in the Square situation.


That is the way I was able to finally visualize this in my head.
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