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Jaytan1
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Please Find x? Updated on: 08 Nov 2018, 18:34
Originally posted by Jaytan1 on 08 Nov 2018, 17:28.
Last edited by Jaytan1 on 08 Nov 2018, 18:34, edited 1 time in total.
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4(2-x)<=5x+8
what is x

a) 9
b) 0
c)<=9
d) >=0
e)<=0

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Please Find x? 08 Nov 2018, 18:28
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4(2-x)≤5x+8
Expand the brackets
8-4x≤5x+8
Add 4x to both sides
8≤9x+8
Subtract 8 from both sides
0≤9x
Divide both sides by 9
0≤x

d) >=0
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Jaytan1
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Please Find x? 08 Nov 2018, 19:53
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philipssonicare
4(2-x)≤5x+8
Expand the brackets
8-4x≤5x+8
Add 4x to both sides
8≤9x+8
Subtract 8 from both sides
0≤9x
Divide both sides by 9
0≤x

d) >=0
Show more

0/9=0 ; so the answer can be e) <=0 as well?

i got -9x<=0
divided both side by -9
not sure zero divided by -9, greater than zero or less than zero; kind of lost
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Please Find x? 08 Nov 2018, 20:35
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Jaytan1
4(2-x)<=5x+8
what is x

a) 9
b) 0
c)<=9
d) >=0
e)<=0
Show more

\(4(2-x)<=5x+8\)

\(8 - 4x <= 5x + 8\)

\(8 - 8 <= 5x + 4x\)

\(0 <= 9x\)

or \(9x >= 0\)

Therefore; \(x >= 0\)

Answer D
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Please Find x? 08 Nov 2018, 20:56
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Jaytan1
You don't know how to do basic algebra and you don't know basics about 0.
I had forgotten them (if I ever did learn them) and started right from the start to improve GMAT. I mean right from the start. I looked at Kindergarten maths on through to high school (and not yet finished) to make sure I didn't miss something basic.

8-9x≤8
-9x≤0
-x≤0
x≥0
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Please Find x? 08 Nov 2018, 21:49
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Shashim,

I totally understand your answer;however could you please tell me what's wrong with the following approach..

4(2-x)≤5x+8
Expand the brackets
8-4x≤5x+8
Subtract 5x from both sides
8-9x≤8
Subtract 8 from both sides
-9x≤0
Divide both sides by -9
x≤0

Answer E



sashiim20
Jaytan1
4(2-x)<=5x+8
what is x

a) 9
b) 0
c)<=9
d) >=0
e)<=0

\(4(2-x)<=5x+8\)

\(8 - 4x <= 5x + 8\)

\(8 - 8 <= 5x + 4x\)

\(0 <= 9x\)

or \(9x >= 0\)

Therefore; \(x >= 0\)

Answer D
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Please Find x? 08 Nov 2018, 22:08
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Jaytan1
Shashim,

I totally understand your answer;however could you please tell me what's wrong with the following approach..

4(2-x)≤5x+8
Expand the brackets
8-4x≤5x+8
Subtract 5x from both sides
8-9x≤8
Subtract 8 from both sides
-9x≤0
Divide both sides by -9
x≤0

Answer E
Show more

Hi Jaytan1,

Note this Property : Whenever you multiply or divide an inequality by a negative number, you must flip the inequality sign.

Therefore when you divide both sides with \(-9\), you will need to flip the inequality sign.

Hence the sign will change in the highlighted portion .

\(x >= 0\)

Answer D

Hope its clear now. :)
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Please Find x? 08 Nov 2018, 22:16
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Jaytan1
Shashim,

I totally understand your answer;however could you please tell me what's wrong with the following approach..

4(2-x)≤5x+8
Expand the brackets
8-4x≤5x+8
Subtract 5x from both sides
8-9x≤8
Subtract 8 from both sides
-9x≤0
Divide both sides by -9
x≤0

Answer E
Show more

You are making mistake in last step,
i.e. Dividing both sides by -9

Because division by negative number reverses the inequality sign
Therefore -9x≤0
Divide both sides by -9, will give

\(x >= 0\)

Answer D

Posted from my mobile device
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Please Find x? 08 Nov 2018, 23:21
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OA:D

\({4(2-x)}\leq{5x+8}\)

\({8-4x}\leq{5x+8}\)

\(x\geq{0}\)

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