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23 Apr 2021, 16:44
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Using digits 1,2,3,4 and 5 form a 2-digit and 3-digit number say ab and cde such that ab x cde is maximum. What are the numbers?
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23 Apr 2021, 20:10
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I would like to share the approach that might work.
As we know the contribution of hundred, tens and units digits are in the proportion of 100, 10 , 1 respectively
so, to get the highest product assign higher digits to hundreds and tens place..
_ _ _* _ _
5_ _ * 4 _
52 _ * 43
521 * 43 = 22403
As we know the contribution of hundred, tens and units digits are in the proportion of 100, 10 , 1 respectively
so, to get the highest product assign higher digits to hundreds and tens place..
_ _ _* _ _
5_ _ * 4 _
52 _ * 43
521 * 43 = 22403
23 Apr 2021, 20:16
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IntellectualMan95
Hi
Never tested IQ, so can’t comment on IQ part, but my approach would be.
ab*cde
Surely a and c should take the biggest => 4 and 5
b and d should take next two => 2 and 3
e for sure will be 1.
Now to work on which value should go to which variable within the two.
ab=10a+b
cde =100c+10d+e
So \(ab*cde =(10a+b)(100c+10d+e)\)
\(1000ac+100ad+100bc+10ae+10bd+e\)
Now a is used more than c, and coefficient are
Coefficients of a are 1000, 100 and 10, while of c are 1000 and 100.
So it will be beneficial to take a>c => a=5, and c=4
Now when coefficient is 100, a is getting multiplied with d, so d should be greater than b=> d=3, and b=2
ab*cde=52*431=22412 should be maximum.
There may be some other method but this is what came to my mind the first.
