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If r = 0.345, s = (0.345)^2, and t = sqrt(0.345) , which of the following is the correct ordering of r, s, and t ?

A. r < s < t
B. r < t < s
C. s < t < r
D. s < r < t
E. t < r < s

CONCEPT:For solving any such question, One must know that

1) If 0<x<1, then the higher powers of x result in smaller numbers and lower powers of x result in a bigger number
2) If x>1, then the higher powers of x result in Bigger numbers and lower powers of x result in a Smaller number




Here since 0.345 is between 0 and 1 therefore

the number with the highest power i.e. s must be least
and the number with the Lowest power i.e. t must be Biggest number

therefore s < r < t

Answer: Option
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Hi All,

This question is based on a couple of important Number Property rules regarding positive fractions (between 0 and 1):

1) When 'squaring' a positive fraction, the result gets SMALLER (e.g.. (1/2)^2 = 1/4).

Since 'square-rooting' is the opposite of 'squaring'....

2) When 'square-rooting' a positive fraction, the result gets BIGGER.

While these rules are not tested that often on the Official GMAT, it's likely that you'll be tested on either or both at least once on Test Day.

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Rich
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Bunuel
If \(r=0.345\), \(s=0.345^2\), and \(t=\sqrt{0.345}\), which of the following is the correct ordering of \(r\), \(s\), and \(t\) ?

A. r < s < t
B. r < t < s
C. s < t < r
D. s < r < t
E. t < r < s

Let \(r = 0.36\) ; \(s = 0.36^2\) & \(t = \sqrt{0.36}\)

So, \(r = 0.36 , s ≈ 0.13\) & \(t = 0.60\)

Thus, \(s < r < t = 0.13 < 0.36 < 0.60\)

Hence, answer will be (D) \(s < r < t\)
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Bunuel
If \(r=0.345\), \(s=0.345^2\), and \(t=\sqrt{0.345}\), which of the following is the correct ordering of \(r\), \(s\), and \(t\) ?

A. r < s < t
B. r < t < s
C. s < t < r
D. s < r < t
E. t < r < s

Since r is a positive decimal between 0 and 1, s = r^2 and t = √r. We see that when r is raised to a power > 1, its value decreases, and when it is raised to a power < 1, its value increases (recall that square root means ½ power). Thus, the correct ordering is s < r < t.

Answer: D
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Solution



Given:
    • r=0.345
    • s=\(0.345^2\)
    • t=√0.345

To find:
    • The correct order of r, s, and t among the given options.

Approach and Working

For 0< x <1:
    • On increasing the power of x, the value of power of x will decrease.
      o For example: 0.5 >\(0.5^2\)

    • On decreasing the power of x, the value of power of x will increase.
      o For example: \(0.5^2\) < 0.5

Thus, we can conclude that: s< r and r <t
• Hence, s < <r < t

Correct answer: Option D
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If r=0.345, s=0.3452, and t=√0.345, which of the following is the correct ordering of r, s, and t ?

A. r < s < t
B. r < t < s
C. s < t < r
D. s < r < t
E. t < r < s

Tricky part of this question is getting rid of that pesky square root for t. Square everything

r=0.345, s=0.3452, and t=√0.345
r^2=0.345^2, s^2=0.3452^2, and t^2=0.345

t > r > s

D.
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