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z102478
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Sole Eqn 27 Mar 2009, 06:26
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Can you explain and solve this one and tell me the roots of x

(x^2-49)(x^2+49)x=0


Thanks



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Sole Eqn 27 Mar 2009, 08:21
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I am damn sure that I am missing something here .....still , here is my answer:

either (x^2-49)=0 OR (x^2+49)=0 OR x=0
for (x^2-49)
x= 7 OR x= -7

For (x^2+49)
x= 7i OR x= -7i

x=0

Please check.
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Sole Eqn 27 Mar 2009, 10:19
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While the above post is entirely correct, complex numbers are not tested on the GMAT - all numbers on the GMAT can be assumed to be real numbers. So the equation has three (real) solutions: -7, 0 and 7.
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z102478
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Sole Eqn 27 Mar 2009, 19:49
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I agree complex nos are not in scope, your answer is correct.

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Sole Eqn 06 Sep 2009, 06:40
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amolsk11
I am damn sure that I am missing something here .....still , here is my answer:

either (x^2-49)=0 OR (x^2+49)=0 OR x=0
for (x^2-49)
x= 7 OR x= -7

For (x^2+49)
x= 7i OR x= -7i

x=0

Please check.
Show more

There is a mistake:
\(x^2+49=0\)
Hence \(x^2=-49\)
This is impossible. This part has no solutions.
H



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