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If a positive integer n is divisible by both 5 and 7, the n must also be divisible by which of the following?

I 12
II 35
III 70

(A) None
(B) I only
(C) II only
(D) I and II
(E) II and III

\(n\) is divisible by both \(5\) and \(7\).

\(n\) will also be divisible by the LCM of \(5\) and \(7\), ie; \(35\).

Answer (C)...
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carcass
If a positive integer n is divisible by both 5 and 7, the n must also be divisible by which of the following?

I 12
II 35
III 70

(A) None
(B) I only
(C) II only
(D) I and II
(E) II and III

Since positive integer n is divisible by both 5 and 7 , it must also be divisible by LCM of 5 and 7 i.e 35
Answer C
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generis
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If a positive integer n is divisible by both 5 and 7, the n must also be divisible by which of the following?

I 12
II 35
III 70

(A) None
(B) I only
(C) II only
(D) I and II
(E) II and III
As above, a number divisible by 5 and 7 will also be divisible by the LCM of 5 and 7, i.e., 35.

The trap answer is 70. Per prime factorization, in order to be sure the number were divisible by 70, we would need to know that integer n also had a factor of 2: (5*7*2) = 70. The prompt doesn't indicate that there is a factor of 2.

Answer C

Hello generis, how is your fantastic life ? :) did you learn anything new today :)

what if question said:

If a positive integer n is divisible by both 5 and 7, the n COULD also be divisible by which of the following? then answer would be 70 ?

i fall in trap, so thats why i am asking this question :)

happy weekend:)
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dave13
generis
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If a positive integer n is divisible by both 5 and 7, the n must also be divisible by which of the following?

I 12
II 35
III 70

(A) None
(B) I only
(C) II only
(D) I and II
(E) II and III
As above, a number divisible by 5 and 7 will also be divisible by the LCM of 5 and 7, i.e., 35.

The trap answer is 70. Per prime factorization, in order to be sure the number were divisible by 70, we would need to know that integer n also had a factor of 2: (5*7*2) = 70. The prompt doesn't indicate that there is a factor of 2.

Answer C
Hello generis, how is your fantastic life ? :) did you learn anything new today :)

what if question said:

If a positive integer n is divisible by both 5 and 7, the n COULD also be divisible by which of the following? then answer would be 70 ?

i fall in trap, so thats why i am asking this question :)

happy weekend:)
Hi dave13 :-)

Your good cheer is refreshing. :thumbup:

See below for what I learned today. :-)

In answer to your question
Quote:
If a positive integer n is divisible by both 5 and 7, the n COULD also be divisible by which of the following? then answer would be 70 ?
Yes. Then the answer would include 35 and 70.
In that case, we deal with
this certainty: \(n\) has
one factor of 5 and one factor of 7
There COULD be a factor of 2 in positive integer n.

If a question depends on \(n\),
and we are not told exactly what \(n\) equals,
or exactly what factors \(n\) has,
it can help to draw "\(n\)" with a little tree diagram
of known factors.

_________n________
____5______7_____?

The key? Put at least one question mark
to remind us that we have
no idea what the other factors are.

Hope that helps. You have a great weekend, too. :-)



Today I learned that a 14-year-old girl in the U.S.
saved up all her money to pay for
a "free laundry day" for her classmates and neighbors during spring break.
She didn't want them to feel ashamed.
I read that story originally on
Good News Network (dated April 4 2018)
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carcass
If a positive integer n is divisible by both 5 and 7, the n must also be divisible by which of the following?

I 12
II 35
III 70

(A) None
(B) I only
(C) II only
(D) I and II
(E) II and III

As n is divisible by both 5 and 7 , the lowest value of n could be 35, which is LCM of 5 and 7. now, what could be the other values of n. n could be 70, 105, 140, 175. All the mentioned numbers will be evenly divisible by only 35. Thus, The correct answer will be C.
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carcass
If a positive integer n is divisible by both 5 and 7, the n must also be divisible by which of the following?

I 12
II 35
III 70

(A) None
(B) I only
(C) II only
(D) I and II
(E) II and III

Let n be 5*7 = 35

35/12-> not an integer
35/35 -> integer
35/70 -> not an integer

so answer is c
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