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Both swan and heron: 0.07
Neither swan nor heron: 0.52
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
72% (01:51) correct
28%
(02:13)
wrong
based on 1412
sessions
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For a randomly selected day, the probability that a visitor to a certain pond will see at least one swan is 0.35. The probability that a visitor to that pond on a randomly selected day will see at least one heron is 0.2. Furthermore, seeing a swan and seeing a heron are independent of each other.
Based on the information provided, select Both swan and heron for the probability that a visitor to the pond will see both at least one swan and at least one heron on any given day, and select Neither swan nor heron for the probability that a visitor to the pond will see neither a swan nor a heron on any given day. Make only two selections, one in each column.
Based on the information provided, select Both swan and heron for the probability that a visitor to the pond will see both at least one swan and at least one heron on any given day, and select Neither swan nor heron for the probability that a visitor to the pond will see neither a swan nor a heron on any given day. Make only two selections, one in each column.
ID: 101096
| Both swan and heron | Neither swan nor heron | |
| 0.02 | ||
| 0.07 | ||
| 0.48 | ||
| 0.52 | ||
| 0.70 |
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Official Answer
Both swan and heron: 0.07
Neither swan nor heron: 0.52
30 May 2024, 18:33
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Both swan AND heron = .2 * .35 = .07
Since the probability of seeing a swan is .35, the probability of not seeing a swan is 1-.35= .65.
Likewise, the probability of not seeing a heron is 1-.2= .8
So, not swan AND not heron is .65 * .8 = .52
Posted from my mobile device
Since the probability of seeing a swan is .35, the probability of not seeing a swan is 1-.35= .65.
Likewise, the probability of not seeing a heron is 1-.2= .8
So, not swan AND not heron is .65 * .8 = .52
Posted from my mobile device
02 Jun 2024, 10:41
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Probability for independent events is - P(A)xP(B)
So, for both events to occur - .2x.35 = .07
for neither of the event to occur = .8x.65 = .52
So, for both events to occur - .2x.35 = .07
for neither of the event to occur = .8x.65 = .52
