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1) Independent Events= P(A & B)=P(A) P(B)=0.35*0.2=0.07
2) (1-P(A))*(1-P(B))=0.65*0.8=0.52
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­Both swan AND heron = .2 * .35 = .07

Since the probability of seeing a swan is .35, the probability of not seeing a swan is 1-.35= .65.
Likewise, the probability of not seeing a heron is 1-.2= .8

So, not swan AND not heron is .65 * .8 = .52
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