For a randomly selected day, the probability that a visitor to

Question

For a randomly selected day, the probability that a visitor to a certain pond will see at least one swan is 0.35. The probability that a visitor to that pond on a randomly selected day will see at least one heron is 0.2. Furthermore, seeing a swan and seeing a heron are independent of each other.

Based on the information provided, select  Both swan and heron  for the probability that a visitor to the pond will see both at least one swan and at least one heron on any given day, and select  Neither swan nor heron  for the probability that a visitor to the pond will see neither a swan nor a heron on any given day. Make only two selections, one in each column.

ID: 101096

DanTheGMATMan · Answer

Both swan AND heron = .2 * .35 = .07

Since the probability of seeing a swan is .35, the probability of not seeing a swan is 1-.35= .65.
Likewise, the probability of not seeing a heron is 1-.2= .8

So, not swan AND not heron is .65 * .8 = .52

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wantawesomescore · Answer

Probability for independent events is - P(A)xP(B)
So, for both events to occur - .2x.35 = .07
for neither of the event to occur = .8x.65 = .52

Oppenheimer1945 · Answer

1) Independent Events= P(A & B)=P(A) P(B)=0.35*0.2=0.07
2) (1-P(A))*(1-P(B))=0.65*0.8=0.52

scrantonstrangler · Answer

Both swan AND heron = .2 * .35 = .07

Since the probability of seeing a swan is .35, the probability of not seeing a swan is 1-.35= .65.
Likewise, the probability of not seeing a heron is 1-.2= .8

So, not swan AND not heron is .65 * .8 = .52

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For a randomly selected day, the probability that a visitor to

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Both swan and heron	Neither swan nor heron
		0.02
		0.07
		0.48
		0.52
		0.70

GMAT Two-part Analysis (TPA) Questions

For a randomly selected day, the probability that a visitor to

Prep Toolkit

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My Rewards