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Apt0810
1)Yes, since if the weight of super judge is thrice the weightage of 1 or 2 than the overall calculation gives the values present in the table.
2)No, since when scores for 1 are increasing than audience scores are decreasing
3)No, since there are more than 3 celebrities with a super judge score of 7(median super judge score)

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median is actually 7.5 and there are 0 people with that score
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Can you provide a quick solution for question 1?
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Weightage of Judge 1, Judge 2: x
Weightage of Super Judge = y
Weightage of Audience: 2(2x+y)

Take celebrity 1 and celebrity 6:
for celebrity 1 you get equation: 7(2x) + 5y = 3(2x+y)(7.27)
for celebrity 6 you get: 9x + 7(5x+3y) = 3(2x+y)(7.13)
On subtracting and simplifying these 2 eqns: 59x = 21y
So, answer to 1st is Yes.
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