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Sajjad1994
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I = (90000(1.05)^5 ) / .5 = 229730 almost equal 230,000

Kindly check ..
Oppenheimer1945
1) graph shows E/I, not E alone, Hence Not Suff

2) E/I =0.5, E=90,000(1+0.05)^3

Using (1+x)^n = 1+nx when x<<1,
E=90,000*1.3

I=2E=180000*1.3=233000 approx­
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Sajjad1994
Over which two consecutive months did Company ABC experience the greatest percentage increase in exports ?

If the estimated exports for Month 1 are USD 90,000 and exports are projected to consistently increase by 5% every month over the next 6 months, what is the approximate value of projected imports for month 6
For Question 1:

Export/ Import is given, from the graph only the ratio can be identified.
Value of import is required in order to identify if the export is decreasing or increasing.

Month 2 and Month 3 option might look tempting. But, there will be sharp rise in exports in this case only if import is constant.
Also the similar situation will arise, when Export is constant but import reduced significantly.

Hence the information provided is not sufficient.

For Question 2:

Month 1 : $90000
Rate : 5%
Month 6 Imports : (90,000*(1.05)^5)/0.5 ~ 230,000
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