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B > 90 and C=A ... if C=A= 30 B= 90 ... so it become an isosceles right triangle. If C=A=38 B will 104.... Option B is correct .
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If the length of side AC is greater than that of BC, then the sides, AB & BC, are of equal length (Since ABC is an isosceles triangle). So, \(\angle\) A = \(\angle\) C = x & \(\angle\) B>\(90^{\circ}\) = y (since ABC is also an obtuse angled triangle). Kindly refer the image.

So, y+2x = 180.....eq-1

There are only two values (104 & 106) greater than 90, so only those values can be the value of y. Substututing those values in eq-1, we get:

Option-1: y=104 & x=38, or
Option-2: y=106 & x=37

Only the corresponding values of Option-1, satisfies the answer options. Hence, the correct answer.
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Can we expect this in gmat FE?
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Can we expect this in gmat FE?

Don't think so. Archiving the question.

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