amanvermagmat
If x and y are real numbers,is |2x - 7| > y ?
(1) y^2 = 16.
(2) x is a negative number.
Posted from my mobile deviceThe question asks is |2x - 7| > y ?
Statement 1 tells us that y^2=16, which means that y=4 or y=-4
Is |2x - 7| > -4? yes always! An absolute value expression is always non negative.
Is |2x - 7| > 4? It may or may not be.
Therefore, statement 1 is not sufficient. Statement 2 tells us that x<0 but doesn't tell us anything about y.
Therefore, statement 2 is also unsufficient.Combining both statements, the question becomes
is |2x - 7| > 4? Solving for the range of this inequality, we get x>11/2 or x<3/2
So any value of x that is greater than 11/2 or less than 3/2 will make this inequality true.
And we know from statement 2 that x<0 , therefore the answer will be yes! because any value of x that is less than 0 (which is less than 3/2) will make the inequality true.
Correct answer is C.