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Bunuel
Is \((4^x)^{(5-3x)}=1\)?

(1) x is an integer.
(2) The product of x and positive integer y is not x.

Given:
\((4^x)^{(5-3x)}=1\)
\((4)^{5x-3x^2} = 4^0\)(As, \((a^m)^n = (a)^{mn})\)
\(x(5 - 3x) = 0\)
is x = 0, is x = \(\frac{5}{3}\)

1) x could be any integer. 0, 1 ,2...
Not sufficient.
2) x * y ≠ x
x is not zero, y ≠ 1
x could be 1, 2, \(\frac{5}{3}\)
Combining 1 & 2:
x ≠ 0, x≠ 5/3
Sufficient. Hence, C
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Bunuel
Is \((4^x)^{(5-3x)}=1\)?

(1) x is an integer.
(2) The product of x and positive integer y is not x.

First of all \((4^x)^{(5-3x)}=4^{x*(5-3x)}\)

For this expression to be equal to 1, \(x*(5-3x)\) must be equal to 0.

\(x*(5-3x)=0\) --> \(x=0\) or \(x=\frac{5}{3}\).

So basically the question asks whether \(x=0\) or \(x=\frac{5}{3}\).

(1) x is an integer, hence x is not 5/3. But we don't know whether x is 0 or any other integer. Not sufficient.

(2) \(xy\neq{x}\), hence x is not equal to 0. But x can be any other number, integer or not integer. Not sufficient.

(1)+(2) x is an integer but not 0. So, x is not 0, not 5/3. Hence \(x*(5-3x)\neq{0}\), hence \((4^x)^{(5-3x)}\) does not equal to 1. Sufficient.

Answer: C.
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