Bunuel
If x^2 + y^2 = 10x, is x < y ?
(1) y = 3
(2) (x - 5)^2 = 16
Given\(x^2 + y^2 = 10x\)
Statement 1y = 3
\(x^2 + 9 = 10x\)
\(x^2 - 10x + 9\)
\((x-1)(x-9)\) = 0
x = 1 or x = 9
As we are getting two possible values of x, one in which x > y and one in which x < y, Statement 1 is not sufficient and we can eliminate A and D.
Statement 2\((x-5)^2 = 16\)
Taking square root on both sides
|x-5| = 4
x = 1 or x = 9
As we are getting two possible values of x, one in which x > y and one in which x < y, Statement 1 is not sufficient and we can eliminate B.
CombinedStatement 1 and Statement 2 give the same information. Hence combining both the statement we do not have any new information. Eliminate C.
Option E
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