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Difficulty:
Question Stats:
27% (02:46) correct 73% (02:35) wrong based on 266 sessionsDivisor (Y) = 1 or 7 and Quotient(Z) = 7 or 1 | |
-Case 1: Y = 1 , Z = 7 Divisor(Y) is 1 And we know that any positive integer divided by 1 will always give 0 as remainder => W = 0 => X = 1*7+0 = 7 And Z = 7 => X and Z become same, but they are different integers Which is NOT POSSIBLE | -Case 2: Y = 7 , Z = 1 Divisor(Y) is 7 => Reminders will be between 0 to 6 => Following cases are possible => W = 0, same as Case 1, so we can ignore this => NOT POSSIBLE => W = 1, Both W and Z = 1 => NOT POSSIBLE X, Y, Z, W all are different in below cases => W = 2, X = 7*1+2 = 9 => POSSIBLE => W = 3, X = 7*1+3 = 10 => POSSIBLE => W = 4, X = 7*1+4 = 11 => POSSIBLE => W = 5, X = 7*1+5 = 12 => POSSIBLE => W = 6, X = 7*1+6 = 13 => POSSIBLE |
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Hi Generic [Bot],
Here are updates for you:
ANNOUNCEMENTS
Watch earlier episodes of DI series below EP1: 6 Hardest Two-Part Analysis Questions EP2: 5 Hardest Graphical Interpretation Questions
Tuck at Dartmouth
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