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AnkurGMAT20
What is the 100th digit to the right of the decimal point in decimal expression of 1/27?

(A) 0
(B) 2
(C) 3
(D) 6
(E) 7
\(\frac{1}{9} = 0.1111.............\)

\(\frac{0.1111}{3} = 0.037037037037...............\)

4th digit ends in 7, so 100 the digit will be 0, Answer must be (A)
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I got this question in one of the Focus practice tests, I solved it by using the classic division method to divide 1 by 27 and figured out the recurring pattern i.e. 037 after the decimal. Knowing the rules for dividing a number smaller than the divisor helped me here.

Lesson: Never ignore elementary mathematical tools; you can use those when all the precast methods to solve a problem fail to apply in certain situations.­
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There has to be a pattern otherwise finding 100th digit would be a herculean task.

If I were to do it, I would try to think about the expression in terms of some more friendly ones.

So,­ \(\frac{1}{27}=\frac{1}{3}\frac{1}{3}\frac{1}{3}=0.3333333*\frac{1}{3}*\frac{1}{3}\)

\(0.111111*\frac{1}{3}\)
Now 111 add up to 3 when digits are added, so should be divisible by 3.

\(\frac{0.(111)(111)(111)...}{3}=0.037037037....\)

Thus 100th digit will come after 33 sets of these three digits 037.
Hence, 0 is the answer.
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chetan2u , Can you please help me understand how you derived that highlighted portion ? 111/3 = 37 only. How did yo arrive at .037..that extra 0..Simply by dividing or any other trick ?
chetan2u
There has to be a pattern otherwise finding 100th digit would be a herculean task.

If I were to do it, I would try to think about the expression in terms of some more friendly ones.

So,­ \(\frac{1}{27}=\frac{1}{3}\frac{1}{3}\frac{1}{3}=0.3333333*\frac{1}{3}*\frac{1}{3}\)

\(0.111111*\frac{1}{3}\)
Now 111 add up to 3 when digits are added, so should be divisible by 3.

\(\frac{0.(111)(111)(111)...}{3}=0.037037037....\)

Thus 100th digit will come after 33 sets of these three digits 037.
Hence, 0 is the answer.
­
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chetan2u , Can you please help me understand how you derived that highlighted portion ? 111/3 = 37 only. How did yo arrive at .037..that extra 0..Simply by dividing or any other trick ?
chetan2u
There has to be a pattern otherwise finding 100th digit would be a herculean task.

If I were to do it, I would try to think about the expression in terms of some more friendly ones.

So,­ \(\frac{1}{27}=\frac{1}{3}\frac{1}{3}\frac{1}{3}=0.3333333*\frac{1}{3}*\frac{1}{3}\)

\(0.111111*\frac{1}{3}\)
Now 111 add up to 3 when digits are added, so should be divisible by 3.

\(\frac{0.(111)(111)(111)...}{3}=0.037037037....\)

Thus 100th digit will come after 33 sets of these three digits 037.
Hence, 0 is the answer.
­

Hi
As also explained above by Bunuel, it is a repeating non terminating decimal. So I picked number of digits that are divisible by 3. Here it is 111, and when you divide it by 3, you get .037.
Now, when I make sets of 111, what I’ll get after division by 3 is sets of 037.

Had it been 1212….., I would have made set of 12 and answer would be 0.0404040….

Posted from my mobile device
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Bunuel ,
Why did you all on a sudden think of converting 1/27 into 37/999 by multiplying both the numerator and the denominator by 37 ?
Any particular reason ?
Bunuel
sayan640
chetan2u , Can you please help me understand how you derived that highlighted portion ? 111/3 = 37 only. How did yo arrive at .037..that extra 0..Simply by dividing or any other trick ?
chetan2u
There has to be a pattern otherwise finding 100th digit would be a herculean task.

If I were to do it, I would try to think about the expression in terms of some more friendly ones.

So,­ \(\frac{1}{27}=\frac{1}{3}\frac{1}{3}\frac{1}{3}=0.3333333*\frac{1}{3}*\frac{1}{3}\)

\(0.111111*\frac{1}{3}\)
Now 111 add up to 3 when digits are added, so should be divisible by 3.

\(\frac{0.(111)(111)(111)...}{3}=0.037037037....\)

Thus 100th digit will come after 33 sets of these three digits 037.
Hence, 0 is the answer.
­
That's because it's not 0.111 there, it’s \(0.\overline{111}\), or simply \(0.\overline{1}\), which means the 1's there repeat indefinitely: 0.111...

What is the 100th digit to the right of the decimal point in decimal expression of 1/27?

(A) 0
(B) 2
(C) 3
(D) 6
(E) 7­


\(\frac{1}{27}=\)

\(=\frac{1}{9}*\frac{1}{3}=\)

\(=0.\overline{111}*\frac{1}{3}=\)

\(=0.\overline{037}\)
(Alternatively, if you recognize that \(\frac{1}{27} = \frac{37}{999}\), you could directly write: \(\frac{1}{27} = \frac{37}{999} = 0.\overline{037}\))

The digits after the decimal repeat in blocks of three (037 - 037 - 037 - ...). Thus, the 99th digit to the right of the decimal point will be 7, and the 100th digit will be 0.

Answer: A.

THEORY:

If you have a fraction where the denominator is 9, 99, 999, etc., the decimal equivalent will have a repeating pattern in the decimal part. The repeating part is just the numerator of the fraction, with enough leading zeroes added to match the number of 9s in the denominator.

Examples:


• \(\frac{2}{9} = 0.2222...\)

• \(\frac{3}{99} = 0.030303...\)

• \(\frac{45}{999} = 0.045045045...\)
Thus, for any fraction \(\frac{n}{999...}\), the decimal representation will be \(0.nnn...\), with the number \(n\) (padded with leading zeroes if necessary) recurring as many times as there are 9s in the denominator.­
 
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Bunuel ,
Why did you all on a sudden think of converting 1/27 into 37/999 by multiplying both the numerator and the denominator by 37 ?
Any particular reason ?
Bunuel
sayan640
Can you please help me understand how you derived that highlighted portion ? 111/3 = 37 only. How did yo arrive at .037..that extra 0..Simply by dividing or any other trick ?
That's because it's not 0.111 there, it’s \(0.\overline{111}\), or simply \(0.\overline{1}\), which means the 1's there repeat indefinitely: 0.111...

What is the 100th digit to the right of the decimal point in decimal expression of 1/27?

(A) 0
(B) 2
(C) 3
(D) 6
(E) 7­




\(\frac{1}{27}=\)

\(=\frac{1}{9}*\frac{1}{3}=\)

\(=0.\overline{111}*\frac{1}{3}=\)

\(=0.\overline{037}\)
(Alternatively, if you recognize that \(\frac{1}{27} = \frac{37}{999}\), you could directly write: \(\frac{1}{27} = \frac{37}{999} = 0.\overline{037}\))

The digits after the decimal repeat in blocks of three (037 - 037 - 037 - ...). Thus, the 99th digit to the right of the decimal point will be 7, and the 100th digit will be 0.

Answer: A.

THEORY:

If you have a fraction where the denominator is 9, 99, 999, etc., the decimal equivalent will have a repeating pattern in the decimal part. The repeating part is just the numerator of the fraction, with enough leading zeroes added to match the number of 9s in the denominator.

Examples:



• \(\frac{2}{9} = 0.2222...\)

• \(\frac{3}{99} = 0.030303...\)

• \(\frac{45}{999} = 0.045045045...\)
Thus, for any fraction \(\frac{n}{999...}\), the decimal representation will be \(0.nnn...\), with the number \(n\) (padded with leading zeroes if necessary) recurring as many times as there are 9s in the denominator.­
­The conversion of 1/27 to 37/999 wasn't done 'all of a sudden.' It is derived from the theory I explained in my previous post, combined with some number sense. As per the theory, all recurring decimals can be expressed as fractions where the denominator is composed of repeated 9s. Thus, 1/27 = n/(repeated 9's). This implies that the denominator should be a multiple of 27 composed of 9s. Checking possibilities, we see that 99 is not a multiple of 27, but 999 is: 999 = 27 * 37. Therefore, 1/27 = 37/999.­
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Hello,

I just got this question from my mock no. 4, here how I approach it:

Manually make "do long division method"
_____
2|1

0.03___
2|100


0.03___
2|100
-81
---
190


0.037___
2|100
-81
---
190
-189
---
1


0.0370___
2|100
-81
---
190
-189
---
100
Here I notice that was again 0 and the divisor is 100, so, I just count by group of 3

037 <---- 7 will be every 3, 30, 60, 90, and 99
So to find 100th will be the next one: In this case 0.

So, answer is:
(A) 0

NalaP.
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Bunuel do you have similar problems to this one?

i got this wrong my mock exam
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for example 1.234 in this tenth digit is 2 and hundredth is 3 . what am i doing wrong ? Bunuel
Bunuel
sayan640
chetan2u , Can you please help me understand how you derived that highlighted portion ? 111/3 = 37 only. How did yo arrive at .037..that extra 0..Simply by dividing or any other trick ?
chetan2u
There has to be a pattern otherwise finding 100th digit would be a herculean task.

If I were to do it, I would try to think about the expression in terms of some more friendly ones.

So,­ \(\frac{1}{27}=\frac{1}{3}\frac{1}{3}\frac{1}{3}=0.3333333*\frac{1}{3}*\frac{1}{3}\)

\(0.111111*\frac{1}{3}\)
Now 111 add up to 3 when digits are added, so should be divisible by 3.

\(\frac{0.(111)(111)(111)...}{3}=0.037037037....\)

Thus 100th digit will come after 33 sets of these three digits 037.
Hence, 0 is the answer.
­
That's because it's not 0.111 there, it’s \(0.\overline{111}\), or simply \(0.\overline{1}\), which means the 1's there repeat indefinitely: 0.111...

What is the 100th digit to the right of the decimal point in decimal expression of 1/27?

(A) 0
(B) 2
(C) 3
(D) 6
(E) 7­

\(\frac{1}{27}=\)

\(=\frac{1}{9}*\frac{1}{3}=\)

\(=0.\overline{111}*\frac{1}{3}=\)

\(=0.\overline{037}\)
(Alternatively, if you recognize that \(\frac{1}{27} = \frac{37}{999}\), you could directly write: \(\frac{1}{27} = \frac{37}{999} = 0.\overline{037}\))

The digits after the decimal repeat in blocks of three (037 - 037 - 037 - ...). Thus, the 99th digit to the right of the decimal point will be 7, and the 100th digit will be 0.

Answer: A.

THEORY:

If you have a fraction where the denominator is 9, 99, 999, etc., the decimal equivalent will have a repeating pattern in the decimal part. The repeating part is just the numerator of the fraction, with enough leading zeroes added to match the number of 9s in the denominator.

Examples:

• \(\frac{2}{9} = 0.2222...\)

• \(\frac{3}{99} = 0.030303...\)

• \(\frac{45}{999} = 0.045045045...\)
Thus, for any fraction \(\frac{n}{999...}\), the decimal representation will be \(0.nnn...\), with the number \(n\) (padded with leading zeroes if necessary) recurring as many times as there are 9s in the denominator.­
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for example 1.234 in this tenth digit is 2 and hundredth is 3 . what am i doing wrong ?

The "100th digit to the right of the decimal point" does not refer to the hundredths digit of 1/27; it refers to the digit located at the 100th position after the decimal point.
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