carcass wrote:

\(\frac{1}{37}\) could be a difficult or at least if not approched well could lead to the wron answer or prone of error

So, do \(\frac{100}{37}\) in this way is more comfortable and in the end you will add 2 zeros

we want the 18 th number and 18 is even

\(\frac{100}{37}\) \(=\) \(270270\) ------------> \(0.0270270\)

Now notice the first number is 0 second 2 third 7 and the fourth again 0

So \(4 * 4 = 16\) in our pattern.

So is \(ZERO\) \(+ 2 = 7\) ( be carefull we are talking of units place not sum)

D is the answer

hi

how can you say so ...?

.027 027 027

here we can see a set of "027" composed of 3 digits, NOT of 4 digits ...

to find the 18th digit, we can arrange 6 identical sets as shown above. Clearly the 18th digit is 7...

thanks ...