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What is the area of the triangle in the figure above?

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What is the area of the triangle in the figure above? [#permalink]

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New post 18 Dec 2017, 20:41
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Question Stats:

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Image
What is the area of the triangle in the figure above?

(A) 4.0
(B) 7.5
(C) 8.0
(D) 8.5
(E) 15.0

[Reveal] Spoiler:
Attachment:
2017-12-19_0836_002.png
2017-12-19_0836_002.png [ 8.18 KiB | Viewed 432 times ]
[Reveal] Spoiler: OA

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Re: What is the area of the triangle in the figure above? [#permalink]

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New post 18 Dec 2017, 23:45
Bunuel wrote:
Image
What is the area of the triangle in the figure above?

(A) 4.0
(B) 7.5
(C) 8.0
(D) 8.5
(E) 15.0

[Reveal] Spoiler:
Attachment:
2017-12-19_0836_002.png


Base of the triangle = Distance between (0,0) and (5,0) = 5 units

Height of the triangle = Distance between (0,0) and (0,3) = 3 units

Area of triangle = (1/2)*Base*Height = (1/2)*5*3 = 7.5

Answer: option B
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Re: What is the area of the triangle in the figure above? [#permalink]

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New post 19 Dec 2017, 09:45
Bunuel wrote:
Image
What is the area of the triangle in the figure above?

(A) 4.0
(B) 7.5
(C) 8.0
(D) 8.5
(E) 15.0

[Reveal] Spoiler:
Attachment:
2017-12-19_0836_002.png


Area of a triangle: \(\frac{base*height}{2}\)

Distance between a point and the origin (0,0): \(\sqrt{x^2+y^2}\)

Base: \(\sqrt{x^2+y^2}=\sqrt{5^2+0^2}=5\)

Height: \(\sqrt{x^2+y^2}=\sqrt{0^2+3^2}=3\)

Area of a triangle: \(\frac{(5*3)}{2}=7.5\)

(B) is the answer.
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Joined: 13 Aug 2017
Posts: 1
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Re: What is the area of the triangle in the figure above? [#permalink]

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New post 19 Dec 2017, 09:54
If we calculate the distance between origin and point on y-axis will give us height

h= 3 units

distance between origin and x-axis point will give the base

b= 5 units

Area = [1/2] *base * height

A= 0.5*5*3 = 7.5 Units
Re: What is the area of the triangle in the figure above?   [#permalink] 19 Dec 2017, 09:54
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