Bunuel wrote:
What is the average (arithmetic mean) annual salary of the 6 employees of a toy company?
(1) If the 6 annual salaries were ordered from least to greatest, each annual salary would be $6,300 greater than the preceding annual salary.
(2) The range of the 6 annual salaries is $31,500.
(1) If the 6 annual salaries were ordered from least to greatest, each annual salary would be $6,300 greater than the preceding annual salary. --- it's an AP with a common difference of 6300
let \(a1= x\)
\(an=a1+ (n-1)d\)
\(n=6\)
\(a6=x+6300(5)= x+ 31,500\)
In an evenly spaced set, mean = \(a1+a6/2\)= \(x+(x+31500)/2\)= \(2x+31500/2 \)this is as simplified as it can get. clearly without knowing x we can't go forward. Insuff.
(2) The range of the 6 annual salaries is $31,500
this is telling us more or less the same thing as the above one. \(a6-a1= 31500\)
if \(a1=x\)
\(a6= x+31500\)
we will get back the same equation:
Arithmetic mean = \(a1+a6/2\)= \(x+(x+31500)/2\)= \(2x+31500/2 \)
Insufficient.
1+2 since we get the same info from both, we can hardly use the combo for something new. C is easy to eliminate.
we're left with E.
not going to lie, I thgt, there must be some way we could get AM, by either of these statements. but sadly, that isn't the case.