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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
68% (01:17) correct
32%
(01:12)
wrong
based on 87
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What is the average (arithmetic mean) mileage of 7 cars in a parking lot?
(1) If the 7 mileages were ordered from least to most, each would be 2.5 miles per gallon higher than the preceding car’s mileage.
(2) The range of the 7 mileages is 15 miles per gallon.
(1) If the 7 mileages were ordered from least to most, each would be 2.5 miles per gallon higher than the preceding car’s mileage.
(2) The range of the 7 mileages is 15 miles per gallon.
09 Jan 2026, 00:06
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ExpertsGlobal5
Average mileage of 7 cars in the parking lot = ?
Statement 1:
If the 7 mileages were ordered from least to most, each would be 2.5 miles per gallon higher than the preceding car’s mileage.
If we arrange the 7 mileages from Least to Most, then the values are
a , a+2.5 , a+5, a+7.5, a+10, a+12.5, a+15
Average Mileage
= (7a+52.5)/7
Without knowing the value of a, we cannot find the average.
Hence, Insufficient.
Statement 2:
The range of the 7 mileages is 15 miles per gallon.
Last value - First value = 15.
Without knowing the First value or Last value, we cannot find average.
Hence, Insufficient.
Combining both, we get
a , a+2.5 , a+5, a+7.5, a+10, a+12.5, a+15
With a being any positive integer, the terms might change, but the range remains the same as 15.
If we find the average, with a=1 the average is different from values with a=2.
Hence, Insufficient.
Option E
09 Jan 2026, 01:19
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ExpertsGlobal5
The average calculation requires the number for sum of the 7 mileages.
Statement 1: Each number is at a gap of 2.5 miles from the previous, i.e. all the numbers are in Arithmetic progression.
in A.P., Mean = Median = (First+Last)/2
But we do NOT have the required number for median or first and last hence
NOT SUFFICIENT
Statement 2: Range = Highest - lowest - 15
Alone NOT SUFFICIENT
Even after comnining the two statements, we lack the sum of first and last or the median hence
NOT SUFFICIENT
Answer: Option E
