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Updated on: 08 Jun 2017, 05:38
Originally posted by GMATinsight on 08 Jun 2017, 04:33.
Last edited by GMATinsight on 08 Jun 2017, 05:38, edited 1 time in total.
Last edited by GMATinsight on 08 Jun 2017, 05:38, edited 1 time in total.
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C
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What is the biggest number that always divides the product of any three consecutive Integers?
A) 2
B) 3
C) 6
D) 12
E) 24
Source: https://www.GMATinsight.com
A) 2
B) 3
C) 6
D) 12
E) 24
Source: https://www.GMATinsight.com
08 Jun 2017, 04:55
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B. 3 will 'always' divide the prod of any 3 cons integers. It is the only hence the biggest such no.
Sent from my SM-J710F using GMAT Club Forum mobile app
Sent from my SM-J710F using GMAT Club Forum mobile app
08 Jun 2017, 05:03
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The answer should be 'C'.
Three consecutive numbers -> x(x+1)(x+2)
will always have one number divisible by 2 and one number divisible by 3
So the product will be a multiple of 2*3 =6
Three consecutive numbers -> x(x+1)(x+2)
will always have one number divisible by 2 and one number divisible by 3
So the product will be a multiple of 2*3 =6
