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Bunuel
What is the greatest prime factor of 8^12 - 2^30?

A. 2
B. 3
C. 5
D. 7
E. 11

8^12 - 2^30?

8 = 2^3
8^12 = 2^36

2^36 - 2^30 = 2^30 (2^6 - 1) = 2^30 (64 - 1) = 2^30 (63) = 2^30 (7*3*3)

hence 2,3,7 are the prime factors of 8^12 - 2^30. here, 7 is the greatest prime factor.

Option D is correct.
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Bunuel
What is the greatest prime factor of 8^12 - 2^30?

A. 2
B. 3
C. 5
D. 7
E. 11

My take:

\(8\)\(^{12}\)\(-\)\(2^{30}\)

\(2\)\(^{3*12}\) \(- 2\)\(^{30}\)

\(2^{36}\) \(- 2^{30}\)

\(2^{30} (2^6-1)\)

\(2^{30} * 63\)

\(2^{30}*3*3*7\)

Hence "7" is the GREATEST prime (D)
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Bunuel
What is the greatest prime factor of 8^12 - 2^30?

A. 2
B. 3
C. 5
D. 7
E. 11

In order to solve this question we need to factor out the set of exponents until we find a prime number.

8^12-2^30
4^24-2^30
(2^24)( 2^12)-2^30
2^36-2^30
2^30-(2^6-1)
2^30-(64-1)
2^30-(63)

prime factorization of 63

(3)(3)(7)

Seven is the largest prime number and thus the answer
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Bunuel
What is the greatest prime factor of 8^12 - 2^30?

A. 2
B. 3
C. 5
D. 7
E. 11

We can simplify the given expression:

(2^3)^12 - 2^30

2^36 - 2^30

2^30(2^6 - 1) = 2^30(63) = 2^30 x 9 x 7 = 2^30 x 3^2 x 7

So the largest prime factor is 7.

Answer: D
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