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Bunuel
What is the perimeter of a square with area 9p^2/16 ?

A. 3p/4
B. 3p^2/4
C. 3p
D. 3p^2
E. 4p/3
Find \(s\).

Area of square = \(s^2 = \frac{9\pi^2}{16}\)

\(\sqrt{s^2} = \frac{(\sqrt{9})*(\sqrt{\pi^2})}{\sqrt{16}}\)

\(s= \frac{3\pi}{4}\)

Perimeter = \(4s=(\frac{3\pi}{4})*4 = 3\pi\)

Answer C
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Area = 9p^2/16
So a^2 = 9p^2/16 ( assumed side of a square as a)

So a = 3p/4
And perimeter of square is sum of all sides
So perimeter = 4a

So ans is 4(3p/4) = 3p



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Bunuel
What is the perimeter of a square with area 9p^2/16 ?

A. 3p/4
B. 3p^2/4
C. 3p
D. 3p^2
E. 4p/3

We know that the area of square = (side)^2

Thus, we can write :
\((Side)^2 = \frac{9p^2}{16}\)

\((Side)^2 = (\frac{3p}{4})^2\)

Since the side of square is always positive, we can conclude that the length of each side \(= \frac{3p}{4}\)

And the perimeter of the square \(= 4 * side = 4 * \frac{3p}{4} = 3p\)

The correct answer is Option C.
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Bunuel
What is the perimeter of a square with area 9p^2/16 ?

A. 3p/4
B. 3p^2/4
C. 3p
D. 3p^2
E. 4p/3

Since a side of the square is equal to √(9p^2/16) = 3p/4, then the perimeter of the square is 4 x 3p/4 = 12p/4 = 3p.

Answer: C
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