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# What is the perimeter of the rectangle having an area of 105

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VP
Joined: 30 Jun 2008
Posts: 1008
What is the perimeter of the rectangle having an area of 105 [#permalink]

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01 Nov 2008, 09:14
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What is the perimeter of the rectangle having an area of 105 ?

(1) The length is greater than twice the width
(2) length and width of the rectangle are integers greater than 5

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Senior Manager
Joined: 21 Apr 2008
Posts: 265
Location: Motortown
Re: DS : KAPLAN : Perimeter of rectangle [#permalink]

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01 Nov 2008, 09:18
B

lb = 105 = 5*7*3

stmt1: InSuff
stmt2: l>5,b>5 ,so l is either 7 or 21 and viceversa for b
Suff
VP
Joined: 30 Jun 2008
Posts: 1008
Re: DS : KAPLAN : Perimeter of rectangle [#permalink]

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01 Nov 2008, 09:56
B it is
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VP
Joined: 15 Jul 2004
Posts: 1358
Schools: Wharton (R2 - submitted); HBS (R2 - submitted); IIMA (admitted for 1 year PGPX)
Re: DS : KAPLAN : Perimeter of rectangle [#permalink]

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01 Nov 2008, 10:00
amitdgr wrote:
What is the perimeter of the rectangle having an area of 105 ?

(1) The length is greater than twice the width
(2) length and width of the rectangle are integers greater than 5

I think it's E.

1 is obviously insuff.

with 2, the possible values for length and width are 35, 3; 21, 5; 15, 7.
So 2 also is insuff because the perimeters are all different with the different set of values.

Combining 1 and 2 also we are able to eliminate only one option because each integer is > 5 so 35 and 3 is out.

It still leaves us with 2 choices. So E.
Current Student
Joined: 28 Dec 2004
Posts: 3292
Location: New York City
Schools: Wharton'11 HBS'12
Re: DS : KAPLAN : Perimeter of rectangle [#permalink]

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01 Nov 2008, 12:42
105=5*21 or 5*7*3..if each side is greater than 5 and is INTEGER only possibility is 7*15

dwivedys wrote:
amitdgr wrote:
What is the perimeter of the rectangle having an area of 105 ?

(1) The length is greater than twice the width
(2) length and width of the rectangle are integers greater than 5

I think it's E.

1 is obviously insuff.

with 2, the possible values for length and width are 35, 3; 21, 5; 15, 7.
So 2 also is insuff because the perimeters are all different with the different set of values.

Combining 1 and 2 also we are able to eliminate only one option because each integer is > 5 so 35 and 3 is out.

It still leaves us with 2 choices. So E.
Intern
Joined: 22 Jul 2008
Posts: 42
Re: DS : KAPLAN : Perimeter of rectangle [#permalink]

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01 Nov 2008, 13:33
How is Stmnt 1 insuff. This is how I see stmnt 1 as being suff. If area = 15* 7 that satisfies the point that length (15) > twice the width (7). Thus, it is sufficient.

Can anyone explain what is that I am missing ???
VP
Joined: 17 Jun 2008
Posts: 1479
Re: DS : KAPLAN : Perimeter of rectangle [#permalink]

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01 Nov 2008, 13:35
rnemani wrote:
How is Stmnt 1 insuff. This is how I see stmnt 1 as being suff. If area = 15* 7 that satisfies the point that length (15) > twice the width (7). Thus, it is sufficient.

Can anyone explain what is that I am missing ???

Stamtment 1 also means 15.1 * 6.9 > twice the width (6.9). That is why it is insufficient.
Intern
Joined: 22 Jul 2008
Posts: 42
Re: DS : KAPLAN : Perimeter of rectangle [#permalink]

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01 Nov 2008, 13:37
Thanks,
I missed the fact that there is no mention about the length and wodth being an integer

--== Message from GMAT Club Team ==--

This is not a quality discussion. It has been retired.

If you would like to discuss this question please re-post it in the respective forum. Thank you!

To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative | Verbal Please note - we may remove posts that do not follow our posting guidelines. Thank you.
Re: DS : KAPLAN : Perimeter of rectangle   [#permalink] 01 Nov 2008, 13:37
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# What is the perimeter of the rectangle having an area of 105

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