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What is the probability that a randomly chosen resident of Town X is

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What is the probability that a randomly chosen resident of Town X is [#permalink]

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New post 25 Aug 2015, 23:16
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What is the probability that a randomly chosen resident of Town X is female?

(1) Town X has 10,000 male residents and 15,000 female residents.

(2) If the number of male residents of Town X were to increase by 20%, the number of male residents of Town X would be 80% of the number of female residents of Town X.

Kudos for a correct solution.
[Reveal] Spoiler: OA

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Re: What is the probability that a randomly chosen resident of Town X is [#permalink]

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New post 26 Aug 2015, 03:05
Bunuel wrote:
What is the probability that a randomly chosen resident of Town X is female?

(1) Town X has 10,000 male residents and 15,000 female residents.

(2) If the number of male residents of Town X were to increase by 20%, the number of male residents of Town X would be 80% of the number of female residents of Town X.

Kudos for a correct solution.


Per the question stem: P(F) = ?

Per statement 1, M = 10k, F = 15k, clearly we can calculate P(F) = F/(F+M) . This statement is sufficient.

Per statement 2, 1.2M = 0.8F ---> F =1.5M

Again , P(F) = F/(F+M) = 1.5M/(1.5M+M) = 1.5/2.5 . Thus this statement is sufficient as well.

D is the correct answer.
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Re: What is the probability that a randomly chosen resident of Town X is [#permalink]

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New post 26 Aug 2015, 09:20
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Bunuel wrote:
What is the probability that a randomly chosen resident of Town X is female?

(1) Town X has 10,000 male residents and 15,000 female residents.

(2) If the number of male residents of Town X were to increase by 20%, the number of male residents of Town X would be 80% of the number of female residents of Town X.

Kudos for a correct solution.



IMO : D

St 1: Town X has 10,000 male residents and 15,000 female residents.

P = 15000/25000 = 3/5
Suff

St 2 : If the number of male residents of Town X were to increase by 20%, the number of male residents of Town X would be 80% of the number of female residents of Town X.

Let No. of male residents = M
Let No. of female residents = F
Thus total = M+F

Given 1.2M = 0.8F
M = 2/3 F

P = \(\frac{F}{(M+F)}\)
= 3/5
Suff
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Re: What is the probability that a randomly chosen resident of Town X is [#permalink]

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New post 26 Aug 2015, 18:17
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probability that a randomly chosen resident of Town X is female?

(1) Town X has 10,000 male residents and 15,000 female residents.
15000/25000
Sufficient

(2) If the number of male residents of Town X were to increase by 20%, the number of male residents of Town X would be 80% of the number of female residents of Town X.
12/10 * M = 8/10 * F
M= 2/3 * F
3/5
Sufficient

Answer:D
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Re: What is the probability that a randomly chosen resident of Town X is [#permalink]

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New post 30 Aug 2015, 08:12
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Bunuel wrote:
What is the probability that a randomly chosen resident of Town X is female?

(1) Town X has 10,000 male residents and 15,000 female residents.

(2) If the number of male residents of Town X were to increase by 20%, the number of male residents of Town X would be 80% of the number of female residents of Town X.

Kudos for a correct solution.


PRINCETON REVIEW OFFICIAL SOLUTION:

Statement 1 is obviously sufficient to answer the question, but Statement 2 is confusing and intimidating. The test writers are trying to get you to choose answer choice A – Statement 1 is sufficient, Statement 2 is not – and that’s exactly what most people will pick. But a smart test-taker sees the trap and guesses that there probably is a way to answer the question using Statement 2 alone, and chooses D – each statement alone is sufficient – the correct answer.

The lesson here is simple:

When you are faced with one easy statement that obviously answers the question, and one complicated statement, the complicated statement probably works, and the answer is probably D.

Wondering how to answer the question using Statement 2 alone?

Statement 2:

Remember that we’re being asked for the probability that resident of Town X is female. To solve for a probability, you don’t need the actual numbers – a percentage, ratio, or fraction will work just fine. We can write an equation with statement 1, if m represents the males and f represents the females:

m + .2m = .8f

1.2m = .8f

Divide both sides by f and by 1.2, and you get:

m/f = .8/1.2 = 8/12 = 2/3

So the ratio of males to females is 2 to 3. From there we can calculate the probability of choosing a male or a female.
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What is the probability that a randomly chosen resident of Town X is [#permalink]

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New post 05 Aug 2016, 06:35
Bunuel wrote:
What is the probability that a randomly chosen resident of Town X is female?

(1) Town X has 10,000 male residents and 15,000 female residents.

(2) If the number of male residents of Town X were to increase by 20%, the number of male residents of Town X would be 80% of the number of female residents of Town X.

Kudos for a correct solution.


(1) Town X has 10,000 male residents and 15,000 female residents.

This statement is Super easy

\(\frac{Female}{Total (Male +Female)} = \frac{15,000}{25,000} = \frac{3}{5}\)= 60%

SUFFICIENT

(2) If the number of male residents of Town X were to increase by 20%, the number of male residents of Town X would be 80% of the number of female residents of Town X.

\(Male = M\)

\(Female = F\)

\(1.2M=0.8F\)

\(12M=8F\)

\(M= \frac{8F}{12}\)

P(Females)= \(\frac{Female}{Female + Male}\)= \(\frac{F}{F+M}\) or\(\frac{F}{F+(8F/12)}\) =\(\frac{12F}{20F}\)= \(\frac{3}{5}= 60\)%

SUFFICIENT

ANSWER IS D
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Re: What is the probability that a randomly chosen resident of Town X is [#permalink]

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Re: What is the probability that a randomly chosen resident of Town X is   [#permalink] 14 Jan 2018, 05:05
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