Bunuel
What is the probability that Lee will make exactly 5 errors on a certain typing test?
(1) The probability that Lee will make 5 or more errors on the test is 0.27.
(2) The probability that Lee will make 5 or fewer errors on the test is 0.85.
NEW question from GMAT® Quantitative Review 2019
(DS06810)
We know that
1 = P (Fewer than 5 errors) + P (Exactly 5 errors) + P (More than 5 errors) ....... (I)
(1) The probability that Lee will make 5 or more errors on the test is 0.27.
P (Exactly 5 errors) + P (More than 5 errors) = 0.27
Putting this in (I) we can get the value of P (Fewer than 5 errors) but we cannot get the value of P (Exactly 5 errors).
Not sufficient
(2) The probability that Lee will make 5 or fewer errors on the test is 0.85.
P (Fewer than 5 errors) + P (Exactly 5 errors) = 0.85
Putting this in (I) we can get the value of P (More than 5 errors) but we cannot get the value of P (Exactly 5 errors).
Not sufficient
Using both,
P (Exactly 5 errors) + P (More than 5 errors) + P (Fewer than 5 errors) + P (Exactly 5 errors) = 0.27 + 0.85
P (Exactly 5 errors) + 1 = 1.12
P (Exactly 5 errors) = 0.12
Sufficient
Answer (C)
Could you please explain why P(Exact 5) is not 0.12/2 = 0.06 as it is added twice