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Bunuel
What is the range of the set 2/3, 8/11, 5/8, 4/7, 9/13 ?

A. 3/56
B. 2/21
C. 11/91
D. 12/77
E. 55/77


chetan2u :
Hi could you please suggest a <2 min way to determine the largest and smallest value from the given set : "2/3, 8/11, 5/8, 4/7, 9/13"
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2/3 > 1/2.
If the difference between numerator and denominator is same same in two fractions, the fraction with highest numerator is greater in value than that of the fraction with lowest.
By that logic, among 4/7, 5/8 and 8/11, 8/11 is the largest.

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nazeernaren
2/3 > 1/2.
If the difference between numerator and denominator is same same in two fractions, the fraction with highest numerator is greater in value than that of the fraction with lowest.
By that logic, among 4/7, 5/8 and 8/11, 8/11 is the largest.

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nazeernaren : agreed but then how will you negate for other two 2/3 and 9/13?
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It is advisable to keep in mind the decimals for fractions of the form 1/x, for 1 <x<=12. That way we can estimate a fraction value in decimal and decide quickly. Hope this is helpful.

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I don't know if this is the best way but you can estimate if you don't remember all the fraction to decimal conversions.

2/3 = .66

For these, I knew that 1/8 = .125 and 1/11 = .09
8/11 = .72
5/8 = .625

I forgot these two, so I got them close to denominator of 100.
4/7*(14/14) = 56/98, (actual is .57)
9/13*(8/8) = 72/104 (actual is .69)

Now I can see that 8/11 is largest and 4/7 is the smallest.
Use LCD 8/11-4/7 = 56/77 - 44/77 = 12/77
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by percent conversion,

we get the smallest 4/7 and the greatest 8/11

So the range is the difference of these two .

The answer is 12/77 option D

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What is the range of the set 2/3, 8/11, 5/8, 4/7, 9/13 ?

A. 3/56
B. 2/21
C. 11/91
D. 12/77
E. 55/77

I used percentages
\(2/3\) = 67%(\(1/3\)= 33% so \(2/3\) = 67%)
\(8/11\) =72%(\(1/11\) =9% so \(8/11\)= 72%)
\(5/8\) = 62.5%(\(1/8\) = 12.5% so\( 5/8\) = 62.5%)
\(4/7\) = 56%(\(1/7\) = 14% so \(4/7\) = 56%)
\(9/13\) = 63%(\(1/13\)=7% so\( 9/13\) = 63%)
Range = L - S = 72% - 56% = 16%
Only Option D \(12/77\) gives 16%
D
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