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This one is really tricky! I don't have an answer yet, but I'm wondering if the fact that \(5^7\) does have a remainder of 47, and that \(5^{91} = (5^7)^{13}\), is significant.

I'm also wondering if 91's proximity to 100 could be useful. If you were to divide any power of 5 (over \(5^1\)) by 100, you would always get a remainder of 25. So perhaps the answer has something to do with using 100 as an approximation and then adding to the remainder.

Very interested to hear others' thoughts!

Edit: formatting
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5^91/91...Remainder?

Solution:
=5^91/91
=5^91/7*13

=Points to observe
5 (num) and 91(deno) are co-primes
Need to factor the denominator,

=We need to develop 2 equations (as 2 factors are there in denom) based on divisibility of individual denominators..

Part:1
=5^91/7
=Based on Euler's theorem, Euler number for prime number at denom. will be 6. (7-1=6)
=dividing 91/6= 6K+1
=so 5^1/7= 5
=5 remainder.
=Equation1 N1= 7A+5

Part:2
=5^91/13
=Based on Euler's theorem, Euler number for prime number at denom. will be 12. (13-1=12)
=dividing 91/13= 12K+7
=so 5^7/13
=25*25*25*5/13
=8 Remainder
= Equation2 N2= 13B+8

Fill the values in Equation N1 (N1= 7A+5), Values are= 5,12,19,26,33,40,47
Fill the values in Equation N2 (N2= 13B+8), Values are= 8,21,34,47

First value satisfying both the equations will be remainder, i.e. 47.

Thanks!
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rahulkashyap
91 = 7*13

Let us find out Rem[5^91/7] and Rem[5^91/13] - using binomial expansion
We will combine them later.

Rem [5^91/7]

= 5(5)^90 / 7
= 5( 125) ^ 30 / 7
=5 (126-1)^30 / 7

remainder = 5. (-1)^30 = 5 / 7
rem = 5



Rem [5^91/13]
= Rem 5. (5)^90 / 13
= 5. (25)^45 / 13
= 5. (26-1)^45)/ 13
remainder = 5. (-1)^45 / 13
= -5/13 = r= 8



So, our answer is a number which leaves a remainder of 5 when divided by 7 and it should leave a remainder of 8 when divided by 13.

simplifying this, we get N= 91K + 47
Hence 47 is the reaminder

How did you arrive at the equation N= 91K + 47 from this statement - is a number which leaves a remainder of 5 when divided by 7 and it should leave a remainder of 8 when divided by 13. Could you pls explain in detail?
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Re(5^91/ 91)
Split 91, the divisor to 13 and 7

Separately find out out the remainders with 13 and 7.
With 7,
E(7)=6, therefore 5^91 actually reduces to Rem(5^1/ 7)----------Remainder is 5; the no is of the form 7a+5
Similarly with 13,
E913)=12, therefore 5^91 actually reduces to Rem(5^7/ 7)----------Remainder is 8; the no is of the form 13b+8
Congruence of these two number types gives 47 the answer. (7a+5=13b+8)
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The methods highlighted by the good folks above are much better for such a question. That said, I wanted to highlight how one can still solve such a question by brute force simplification.


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Harsha
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