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81 when divided by 17 gives a remainder of -4
81^2 when divided by 17 gives a remainder of -4*-4 i.e. 16 i.e. -1
81^4 when divided by 17 gives a remainder of 1
82/4 will give a remainder of 2
81^82 = 81^2 when divided by 17 gives a remainder of 16
therefore option E
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What is the remainder when \(81^{82}\) is divided by 17 ?

The remainder when \(81^{82}\) is divided by 17
= The remainder when \((17*5-4)^{82}\) is divided by 17
= The remainder when \((-4)^{82}\) is divided by 17
= The remainder when \((4)^{82}\) is divided by 17
= The remainder when \((16)^{41}\) is divided by 17
= The remainder when \((17-1)^{41}\) is divided by 17
= The remainder when \((-1)^{41}\) is divided by 17
= The remainder when -1 is divided by 17
= 17-1 = 16

IMO E
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