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Bunuel
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Bunuel please explain how the final step is done. cant understand how x-4/x+2 is translated to -2<x<4
nick1816
\(\frac{(x-1)(x+4)}{(x+2)} <x\)

\(\frac{(x-1)(x+4)}{(x+2)} -x<0\)

\(\frac{x-4}{x+2}<0\)

-2<x<4


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Su1206
Bunuel please explain how the final step is done. cant understand how x-4/x+2 is translated to -2<x<4


We have:

\(\frac{x-4}{x+2}<0\)

The transition points are x = -2 and x = 4 (these are the values of x for which the numerator or denominator equals 0). This gives us three ranges:

\(x < -2\)
\(-2 < x < 4\)
\(x > 4\)

Next, test an extreme value for x: if x is a large enough number, say 10, then both the numerator and denominator will be positive, resulting in a positive value for the whole expression. Therefore, when x > 4, the expression is positive. Now, here’s the trick: since the expression is positive in the 3rd range, it will be negative in the 2nd range and positive again in the 1st range, following the pattern: +, -, +. Thus, the expression is negative for \(-2 < x < 4\).

Inequalities

Theory:

Questions:

For more check Ultimate GMAT Quantitative Megathread

Hope it helps.­
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