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Bunuel
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I just looked for all the factor pairs of the numbers, starting with 60.

Factor pairs of 60:
1 * 60
2 * 30
3 * 20
4 * 15
5 * 12
6 * 10

And that's it...answer is A.
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Concept: When we are Given the Total Count of Factors of a Number and need to decide the MINIMUM Value that Number can take, the goal should be to try and perform "Maximum Splitting" with the Prime Factors ---- b/c Powers grow Exponentially very Quickly


What I mean is, if the Total Factors of a Number = 12

then understanding the Logic behind the Find the Total Factors Rule, you should look to try and "SPLIT" the Powers of the Prime Bases up as much as you can.

If All the Variables are Prime Numbers, for instance the Number can be:

a^11

or

a^5 * b^1

or

a^3 * b^2 ----- Total Factors = (3 + 1) * (2 + 1) = 4 * 3 = 12 Total Factors

or

a^1 * b^1 * c^2 ---- Total Factors = (1 + 1) * (1 + 1) * (2 + 1) = 12 Total Factors


The Last Case in which the Powers are "SPLIT" between the Prime Bases as much as possible is likely the Minimum Value we can Find that will have 12 Factors.

Assign the Smallest Prime Factor of 2 to Variable c.

2^2 * 3^1 * 5^1 = 4 * 3 * 5 = 60

This is the Minimum Value we can find that has 12 Factors
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