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13 Mar 2020, 05:10
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B
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What is the sum of all the integers from 20 to 50, inclusive?
(A) 990
(B) 1,085
(C) 1,167
(D) 1,197
(E) 1,267
(A) 990
(B) 1,085
(C) 1,167
(D) 1,197
(E) 1,267
13 Mar 2020, 05:22
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Bunuel
What is the sum of all the integers from 20 to 50, inclusive?
(A) 990
(B) 1,085
(C) 1,167
(D) 1,197
(E) 1,267
(A) 990
(B) 1,085
(C) 1,167
(D) 1,197
(E) 1,267
Arithmetic progression is the series of terms in which terms in ascending order are equispaced
Sum of any Arithmetic Progression (A.P.) = (n/2)*[First term + Last Term]
n = Number of terms
Total Terms from 20 to 50, n = 1 to 50 - 1 to 19 = 50 - 19 = 31
First term = 20
Last term = 50
Required Sum = (31/2)*[20+50] = 1085
Answer: Option B
13 Mar 2020, 05:26
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Bunuel
What is the sum of all the integers from 20 to 50, inclusive?
(A) 990
(B) 1,085
(C) 1,167
(D) 1,197
(E) 1,267
(A) 990
(B) 1,085
(C) 1,167
(D) 1,197
(E) 1,267
A nice rule says: the number of integers from x to y inclusive equals y - x + 1
So, the number of integers from 20 to 50 inclusive = 50 - 20 + 1 = 31
Since the values are EQUALLY SPACED, the average value = the average of the least and greatest values.
So, the average = (50 + 20)/2 = 35
So, there are 31 numbers with an average value of 35
The sum = (31)(35)
= 1,085
Answer: B
Cheers,
Brent
