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16 Mar 2020, 23:43
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
75% (02:07) correct
25%
(02:17)
wrong
based on 333
sessions
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Time
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Not Attempted Yet
What is the sum of every integer between 100 and 300 that has a units digit of 3 ?
A) 2,730
B) 3,960
C) 4,450
D) 5,120
E) 7,920
A) 2,730
B) 3,960
C) 4,450
D) 5,120
E) 7,920
17 Mar 2020, 00:06
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CAMANISHPARMAR
Numbers to be added are
103 + 113 + 123 + 133 + ..... + 293
It's an Arithmetic Progression
Sum of Arithmetic Progression = (n/2) [First term + Last term]
where n - number of terms
Every 100 numbers have 10 such terms with unit digit 3
i.e. n = 20 as we are dealing with 200 consecutive numbers
hence, Sum = (20/2) [103+293] = 3960
Answer: Option B
General Discussion
09 Apr 2020, 04:43
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I solve as follow:
I if sum: 3+13+26+...93= 480,with this number I have to sum 100 in each one that is equal to 100*10+480=1480,
similar to 200= 480+2000, and 300=480+3000, the sum of 1480+2480+3480= 7740.
Please help me I'm confused and my numbers look consistently.
I if sum: 3+13+26+...93= 480,with this number I have to sum 100 in each one that is equal to 100*10+480=1480,
similar to 200= 480+2000, and 300=480+3000, the sum of 1480+2480+3480= 7740.
Please help me I'm confused and my numbers look consistently.
