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23 Jun 2020, 09:40
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B
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Difficulty:
15%
(low)
Question Stats:
79% (00:57) correct
21%
(02:02)
wrong
based on 102
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What is the total number of positive factors of 6400?
A. 24
B. 27
C. 54
D. 68
E. 72
A. 24
B. 27
C. 54
D. 68
E. 72
What is the total number of different divisors including 1 and the number that can divide the number 6400?
(1) 24 (2) 27 (3) 54 (4) 68
(1) 24 (2) 27 (3) 54 (4) 68
yashikaaggarwal
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23 Jun 2020, 09:47
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Factors of 6400 = 2*2*2*2*2*2*2*2*5*5
=> 2^8*5^2
The number of factors = (8+1)(2+1) = 9*3 = 27
IMO B
Posted from my mobile device
=> 2^8*5^2
The number of factors = (8+1)(2+1) = 9*3 = 27
IMO B
Posted from my mobile device
23 Jun 2020, 09:52
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Factors of 6400 are - 2^8 * 5^2
Total numbers of factors is given by - (Power of 1st prime factor +1) * (Power of 2nd prime factor +1) * and so on
Therefore, Answer = (8+1)*(2+1) =27
That is choice B.
[size=80][b][i]Posted from my mobile device[/i][/b][/size]
Total numbers of factors is given by - (Power of 1st prime factor +1) * (Power of 2nd prime factor +1) * and so on
Therefore, Answer = (8+1)*(2+1) =27
That is choice B.
[size=80][b][i]Posted from my mobile device[/i][/b][/size]
